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3 years ago

-V2.25 Find the square root

Mathematics

1 answer:

horrorfan [7]3 years ago

8 0

Answer: there is no number (NaN)

Step-by-step explanation:

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4 yd 8 in + 6 yd 6 in=?

spin [16.1K]

Answer:

10 yd 15 in, or 10.33 3 in.

If one foot is .33 repeating of a yard, then

10.33 3 inches is your answer.

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4 years ago

A rocket travels in a trajectory given by the equation s = -4.9t 2 + v0t, where s is meters above ground, t is time in seconds a

Reptile [31]

Step-by-step explanation:

s = -4.9t² + 49t

The vertex of the parabola is at t = -b/(2a).

t = -49 / (2 × -4.9)

t = 5

The rocket reaches its maximum height after 5 seconds.

5 0

3 years ago

I need to solve for b but I don't know how

lorasvet [3.4K]

It base times height

5 0

3 years ago

Nellie took a total of 27 quizzes over the course of 3 weeks. After attending 4 weeks of school this quarter, how many quizzes w

Dennis_Churaev [7]

Answer:

The answer is 36

Step-by-step explanation:

If you do 27÷3 you get 9. So if it's 4 weeks you just add 9 which is 36

4 0

3 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

6 0

3 years ago