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Paha777 [63]
3 years ago
8

-V2.25 Find the square root

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer: there is no number (NaN)

Step-by-step explanation:

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Find the perimeter and area of the rectangle
Damm [24]

Answer:

area is 8 perimeter is 12

Step-by-step explanation:

8 0
2 years ago
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Which is right??????
victus00 [196]

Answer:

Point D

Step-by-step explanation:

To draw a perpendicular bisector between BE, you have take more than half of the length BE on the compass. So, it should be D

5 0
3 years ago
What is 9/14 x 2 1/3!!!!
pshichka [43]
The answer is 11
Explaination:
9/14 multiple both numbers by 3=27/42
Break 2 1/3 into 2 and 1/3
1/3 multiple both numbers but 14=14/42
27/42 x 14/42 keep number on the bottom the same
27x14= 378
Divide 378/42=9
Add the 2 from 2 1/3 to the nine
2+9=11
8 0
2 years ago
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Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
Can someone help please
m_a_m_a [10]

Answer:

What do you need help with?

Step-by-step explanation:

4 0
2 years ago
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