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Vera_Pavlovna [14]
3 years ago
5

Help plssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

12.6875 (rounded decimal: 12.69)

Step-by-step explanation:

Turn 1 3/4 into a decimal then multiply

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What is the quotient of d − 2 √ d 4 − 5 d 3 + d + 17
Tcecarenko [31]

Answer: d^3 - 3d^2-5

Step-by-step explanation:

For finding the quotient of the given division,

In the long division method, we will follow the following steps.

Step 1 : Here the divisor is d-2 and dividend is d^4-5 d^3 + d + 17

Multiply (d-2) by d^3  and subtract the dividend by the resultant.

We get -3d^3+d

Step 2: Multiply (d-2) by -3d^2  and subtract the remaining dividend by the resultant.

We get  -5d^2+17

Step 3 : Multiply (d-2) by -5  and subtract the remaining dividend by the resultant.

We get  7

Since, after getting 7 it is not possible further division,

Hence, Remainder = 7,

Quotient = sum of all expression by that we multiply (d-2) = d^3 - 3d^2-5

4 0
3 years ago
Find the straight line f(x) which intersects the coordinates (8,0) and (1, -7).
Delvig [45]

Answer:

y = x - 8

Step-by-step explanation:

7/7X - 8

the y intercept was the only tricky part

4 0
3 years ago
Read 2 more answers
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
3 years ago
you put the names of all the students in your class in a paper bag. there are 15 boys and 11 girls. if you drawa name at random
rosijanka [135]
There is a 15/26 chance that it will be a boy
8 0
3 years ago
The sum of eight times a number and fifteen is seven find the number
dmitriy555 [2]
Form an equation then solve:

8x+15=7
8x=-8
x=-1
3 0
3 years ago
Read 2 more answers
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