The first thing we are going to do is find the equation of motion:
ωf = ωi + αt
θ = ωi*t + 1/2αt^2
Where:
ωf = final angular velocity
ωi = initial angular velocity
α = Angular acceleration
θ = Revolutions.
t = time.
We have then:
ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
ωi = 0
α = 190 rad / s2
Clearing t:
753.60 = 0 + 190*t
t = 753.60 / 190
t = 3.97 s
Then, replacing the time:
θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
θ1 = 1494.51 rad
For (10-3.97) s:
θ2 = ωf * t
θ2 = (753.60 rad / s) * (10-3.97) s
θ2 = 4544,208 rad
Number of final revolutions:
θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
θ1 + θ2 = 961.57 rev
Answer:
the disk has made 961.57 rev 10.0 s after it starts up
Answer:
See explaination
Explanation:
class YourSimpleLinkedList<E> extends SimpleLinkedList<E> {
public boolean search(E value) {
if (value == null)
throw new IllegalArgumentException();
Item temp = start;
while (temp != null) {
if (temp.value.equals(value))
return true;
temp = temp.next;
}
return false;
}
}
Answer: Combines multiple network storage devices so they appear to be a single device.
Explanation: In this case, different physical devices, that normally are accessed separately as different drives, are treated by the operating system, like they were only one "giant drive" , hidding from the user the details regarding how it is done, creating in this way a virtual storage, a single logic unit.
Answer:
The correct answer is letter "B": segmenting computer servers to perform dedicated functions.
Explanation:
Computer segmentation refers to separating a server from the rest of the computers within the same network. The segmentation can separate one computer from others or groups of servers from one another. Thew type of segmentation will always depend on the device used to do the separation of the servers.
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