Answer:
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- int num[] = new int[51];
- Scanner input = new Scanner(System.in);
- System.out.print("Number of input: ");
- int limit = input.nextInt();
- for(int i=0; i < limit; i++){
- System.out.print("Input a number (1-50): ");
- int k = input.nextInt();
- num[k]++;
- }
- for(int j=1; j < 51; j++){
- if(num[j] > 0){
- System.out.println("Number of occurrence of " + j + ": " + num[j]);
- }
- }
- }
- }
Explanation:
The solution is written in Java.
Firstly, create an integer array with size 51. The array will have 51 items with initial value 0 each (Line 5).
Create a Scanner object and get user entry the number of input (Line 6-7).
Use the input number as the limit to control the number of the for loop iteration to repeatedly get integer input from user (Line 9-13). Whenever user input an integer, use that integer, k, as the index to address the corresponding items in the array and increment it by one (LINE 11-12).
At last, create another for loop to iterate through each item in the array and check if there is any item with value above zero (this means with occurrence at least one). If so, print the item value as number of occurrence (Line 14-17).
Answer:
Users of the application may have the ability to determine information about the locations of users that are not on their contact list.
Answer:
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Explanation:
it can be difficult. For me it was one of the most challenging classes but also one of the my most interesting ones. You gain an understanding of what occurs at 7 different layers of abstraction (similar in theory to the OSI model used in networking but different). It can be hard
<span>The first stage in the transmission of a car with a manual gearbox is the clutch.</span>