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3 years ago

20 pt what do you see

Mathematics

1 answer:

GrogVix [38]3 years ago

8 0

A watermarked picture by Shutterstock, known as a stock photo with the photo displaying "LOL" and comic like explosion.

I have no idea what you are asking about so I will take your question literally.

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4. The Blackhawk Eagles scored 4 points more than the Lane Vikings. The

konstantin123 [22]

Answer:

Lane Viking's Score is 17

Black Eagles's Score is 21

Step-by-step explanation:

Let Lane Viking's Score be x and Black Eagles's Score be y.

Black Eagles's Score = 4+ Lane Viking's Score

so y = 4 + x (Equation 1)

Total Score = 38

Black Eagles's Score + Lane Viking's Score = 38

so y + x =38 (Equation 2)

Putting y's value from Equation 1 in Equation 2

4 + x + x = 38

2x = 38-4

x=34/2

x=17

Putting value of x in Equation 1

y = 4 + 17

y = 21

7 0

3 years ago

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago

at the cafe, Rebecca can choose to earn $10 per hour plus a $60 starting bonus or earn $12 per hour with no starting bonus. afte

qwelly [4]

Hi there! The answer is 30 hours.

Let the number of worked hours be represented by X.

The total earn of option 1, would then be 10X + 60
The total earn of option 2, would then be 12X

We end up with the following equation:
$10x + 60 = 12x$
Subtract 10X from both sides.

$60 = 2x$
Divide both sides by 2.

$x = 30$
Therefore, after 30 hours of work Rebecca will earn the same amount of money.

8 0

3 years ago

Find the x- and y-intercepts for the linear equation.<br><br> 6. x + y = -3

Artyom0805 [142]

Loserrrrrrrrrrrrrrrrr

8 0

4 years ago

Read 2 more answers

How is 1/x + 2 - 4/2x +1 equivalent to - 2x + 7 / (x + 2)(2x + 1)

DanielleElmas [232]

We have,

$\frac{1}{x + 2} - \frac{4}{2x + 1} \\$

Since the denominator isn't same we cannot directly perform any arithmetic operation on the terms, in order to be able to do that we must make the denominator same,

It's like the way we have,
$\frac{2}{3} + \frac{4}{9} \\$

You know you cannot just add the terms and write the answer as,
$\frac{8}{12} \\$
It completely wrong.

each of the terms have different values when when added doesn't gives 8/12.

Let me prove that to you by converting them into decimal values,

so
$\frac{2}{3} = 0.67 \\ \\ and \\ \\ \frac{4}{9} = 0.43$
Adding these two gives, 1.1

and
The result we had earlier equates to,
$\frac{8}{12} = \frac{4}{3} = 1.33 \\$

You see the results are not equal.

So there must be something wrong.

And the wrong this here was not making the denominators equal,
To do that you basically multiply 2/3 with a 3/3 which may look stange at first but it does gives you same denominator as 4/9 in the form of 6/9.

Now you can add the numerators up and leave the denominator as it is which will give 10/9 = 1.1

Back to you question to show that the terms sperated by = are equal we must show one is identical to another.

Let's do this using the Right hand side,

$\frac{( - 2x + 7)}{(x + 2)(2x + 1)} \\ \\ = \frac{(2x + 1) -4 (x + 2)}{(x + 2)(2x + 1)} \\ \\ = \frac{(2x + 1)}{(x + 2)(2x + 1)} - \frac{4(x + 2)}{(x + 2)(2x + 1)} \\ \\ \frac{1}{x + 2} - \frac{4}{2x + 1}$

Now this value is clearly equal to the the one on the left hand side of "=" .

3 0

3 years ago