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denis-greek [22]
3 years ago
9

24 - 4 x 2 + 4b = 20 - 16​

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

b = -3

Step-by-step explanation:

Solve for b:

4 b - 4 2 + 24 = 20 - 16

-4×2 = -8:

4 b + -8 + 24 = 20 - 16

Grouping like terms, 4 b - 8 + 24 = 4 b + (24 - 8):

4 b + (24 - 8) = 20 - 16

24 - 8 = 16:

4 b + 16 = 20 - 16

20 - 16 = 4:

4 b + 16 = 4

Subtract 16 from both sides:

4 b + (16 - 16) = 4 - 16

16 - 16 = 0:

4 b = 4 - 16

4 - 16 = -12:

4 b = -12

Divide both sides of 4 b = -12 by 4:

(4 b)/4 = (-12)/4

4/4 = 1:

b = (-12)/4

The gcd of -12 and 4 is 4, so (-12)/4 = (4 (-3))/(4×1) = 4/4×-3 = -3:

Answer: b = -3

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Answer:

135

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8 0
2 years ago
Which equation represents the graph below
andreyandreev [35.5K]

Answer: b. -2x+3y=12

Step-by-step explanation: the y intercept is 4, and the line intercepts the x- axis at -6. Therefore, the slope of the line is 4/6=2/3. The format for a linear equation is y=(slope)x+y intercept. So the equation would be y=2/3x+4. You can see that answer b simplifies to that. Add 2x from both sides of the equation and you get 3y=2x+12. Divide both sides of the equation by 3 and you get y=2/3x+4

8 0
3 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
Exit
Nat2105 [25]
The answer is D plane Qpr
3 0
3 years ago
29
nevsk [136]

Answer:

69 need to be added

Step-by-step explanation:

1300 +69 = 1369

37 ²  = 1,369

square root of 1,369 is 37

5 0
3 years ago
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