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Naya [18.7K]
3 years ago
15

What is the perimeter of this figure?

Mathematics
2 answers:
kompoz [17]3 years ago
5 0

Answer:210. 2/3

you would have to add all the numbers to get the answer even the fractions

Leya [2.2K]3 years ago
4 0

Answer:

230.6 or 692/3

Step-by-step explanation:

365/6 + 326/6 + 356/6 + 337/6 = 1384/6 = 692/3 = 230.6

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The following equation is true for all values of x. Write the number that completes the equation. Show your work.
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A man is 37 years old and his child's age is 8. How many years ago was the product of their ages 96?
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Round each number to the nearest tenth. What is the best estimate for the answer to 382.24 – 297.28?
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8 0
3 years ago
Read 2 more answers
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met
Sav [38]

Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

<u>Question asked:</u>

How many kilometres from the hole was Martin when he started?

<u>Solution:</u>

Let distance from Martin starting point to the hole in meters = x

On Martin's first stroke, ball traveled = \frac{4}{5} \ of \ total \ distance\ to\ the\ hole

                                                             =\frac{4}{5} \times x=\frac{4x}{5}

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters

Now, convert it into kilometre:

1000 meter = 1 km

1 meter = \frac{1}{1000}

395 meters = \frac{1}{1000}\times395=0.395\ kilometre

Thus, there are 0.395 kilometre distance from Martin starting point to the hole.

8 0
3 years ago
A poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ag
Katyanochek1 [597]

Answer:

At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

Step-by-step explanation:

Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.

Let five years ago be group I X and as of now be group II Y

H_0: p_x =p_y\\H_a: p_x \neq p_y

(Two tailed test at 5% level of significance)

                Group I            Group II              combined p

n                  270                 300                         570

favor            120                  140                          260

p                   0.4444            0.4667                   0.4561

Std error   for differene = \sqrt{\frac{0.4561(1-0.4561)}{570} } \\=0.0209

p difference = -0.0223    

Z statistic = p diff/std error =       -1.066

p value =0.2864

Since p value >0.05, we accept null hypothesis.

        At 5% significance level, it is statistically evident that    there is nodifference in the proportion of college students who consider themselves overweight between the two poll                                  

7 0
3 years ago
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