Answer:
The coordinates of the vertices of triangle Q'R'S' will be:
Step-by-step explanation:
Given the coordinates of the vertices QRS
The coordinates of the vertex Q is (-2, 3)
The coordinates of the vertex R is (-5, -3)
The coordinates of the vertex Q is (2, -4)
As we know the rules of translation that:
If you move horizontally 'c' units to the left, then 'c' units are subtracted to the x-coordinate of each of the vertices.
if you move 'c' units up, then 'c' units are added to the y-coordinate of each of the vertices.
Translation 6 units up and 4 units to the left.
(x, y) → (x - 4, y + 6)
As the triangle Q'R'S' is the image of the triangle QRS translated 6 units up and 4 units to the left.
So,
the coordinates of Q' will be:
(x, y) → (x - 4, y + 6) = (x, y) → (-2 - 4, 3 + 6) = (-6, 9)
the coordinates of R' will be:
(x, y) → (x - 4, y + 6) = (x, y) → (-5 - 4, -3 + 6) = (-9, 3)
the coordinates of S' will be:
(x, y) → (x - 4, y + 6) = (x, y) → (2 - 4, -4 + 6) = (-2, 2)
Therefore, the coordinates of the vertices of triangle Q'R'S' will be:
