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butalik [34]
3 years ago
9

I have no idea how to even begin this question. Thank you!

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

  • sin(x) = ±(√2)/2
  • r.a. = 45°
  • x = 45° +k·360°
  • x = 135° +k·360°
  • x = 225° +k·360°
  • x = 315° +k·360°
  • x ∈ {135°, 225°, 315°, 405°}

Step-by-step explanation:

Start by solving for sin(x).

  4sin(x)² = 2

  sin(x)² = 1/2 . . . . divide by 4

  sin(x) = ±√(1/2) = ±(√2)/2

Use your knowledge of the sine function to recognize that the reference angle is 45°, and that the angles x will be ...

  x = ±45° or 180°±45°   with multiples of 360° added

The solutions in the desired range are ...

  x ∈ {135°, 225°, 315°, 405°}

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3 years ago
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marshall27 [118]

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8 0
3 years ago
Read 2 more answers
Help please and thank you
gulaghasi [49]

Answer:

56

Step-by-step explanation:

Missing length = x + 21

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3 years ago
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