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Licemer1 [7]
3 years ago
13

Use the roster method to write each of the given sets. For some exercises you may need to consult a reference, such as the Inter

net or an encyclopedia. (Enter EMPTY for the empty set.)
The set of natural numbers x that satisfy x + 2 = 1
Mathematics
1 answer:
castortr0y [4]3 years ago
4 0

Answer:

The empty set \{ \}

Step-by-step explanation:

Roster method is simply listing explicitly all the elements in the set, one by one (writing them between two curly brackets, and separating them through commas).

We want then to list explicitly all the elements in the following set:

The set of natural numbers x that satisfy x+2=1.

So, first we have to figure out which numbers are in that set. The set is made ONLY of those natural numbers x, that when you add 2 to them, you get 1. Clearly no natural number has that property (since the only number that would give us 1 when adding 2 to it, is the number -1, which is NOT a natural number). So there aren't any numbers at all in that set. So if we were to list them, we'd just list nothing inside the set:

\{ \} (which is just the empty set)

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3 years ago
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8_murik_8 [283]

Answer:

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Step-by-step explanation:

divide 8 by 15 and you get 0.53 explanation As a decimal 8/15 is 0.533 (3 repeating) or about 0.53. To convert 8/15 into a decimal value we simply divide 8 by 15. Since 15 cannot be divided into 8 we add a decimal and a zero then divide 15 into 8, giving us 5 with 5 remaining. Adding another zero allows us to divide 15 into 50 3-times with 5 remaining.

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2 years ago
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Butoxors [25]

Answer:

1a. 58/99

1b. 53/90

1c. 29/50

Step-by-step explanation:

let's start with the easiest one

1.(c)

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that is the simplest possible form, as 29 is a prime number and not a factor of 50.

1.(a)

0.585858585858... = 58×0.0101010101010101...

now, we know that 1/"double digit" (like 1/22) mostly produces a repeating pattern with a period length of 2 after the decimal point.

and we find

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so, our solution is

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that is the simplest possible form, as 58 and 99 do not share any factors.

1.(b)

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we know how to create 0.11111111111... :

1/9 = 0.111111111111111...

so, our solution is

0.5 + 8 × 1/10 × 1/9 = 0.5 + 8/90 = 5/10 + 8/90 =

= 45/90 + 8/90 = 53/90

this is the simplest possible form, as 53 is already a prime number and not a factor of 90.

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