Therefore, the function is not differentiable at x = 1.
Therefore, the function is not differentiable at x = 0.
Evaluate x(–y + z) for x = 3, y = 3, and z = 1. –8 –6 12 10
1 answer:
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Therefore, the function is not differentiable at x = 1.
Therefore, the function is not differentiable at x = 0.
Answer:
Step-by-step explanation:
This is a recurring decimal.
Let x = 4.666666... ⇒ (1)
10x = 46.66666... ⇒ (2)
Subtract equation (1) from equation (2)
10x = 46.66666..
-<u> x = 4.666666... </u>
<u> 9x = 42.0000.....</u>
<u />
9x = 42
x = 42/9
= 14/3
=
Answer:
y = 4
Step-by-step explanation:
Given the equation of the line, y = 6, passing through point (3, 4):
By definition, parallel lines have the <u>same slope</u>.
The linear equation, y = 6 is a horizontal line with a zero slope. Therefore, the parallel line must also have the same slope = 0.
Plug the given values from the point (3, 4) into the slope-intercept form:
y = mx + b
where: y = 4, m = 0, and x = 3. We need to solve for the y-intercept, b:
y = mx + b
4 = 0(3) + b
4 = 0 + b
4 = b
Therefore, the y-intercept is (0, 4).
For horizontal lines, the y-coordinate = 4 stays the same, while having different x-coordinates.
Therefore, the equation that is parallel to y = 6 is y = 4.
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