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zhannawk [14.2K]
3 years ago
10

Evaluate x(–y + z) for x = 3, y = 3, and z = 1. –8 –6 12 10

Mathematics
1 answer:
brilliants [131]3 years ago
6 0

Answer:

-6

Step-by-step explanation:

3(-3+1)

-9+3

=-6

substitute the value

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Anyone know this one I’m kinda bad at math lol
swat32

Answer:

1/ 9^5

Step-by-step explanation:

When dividing exponents with the same base, subtract the exponents

9^2 / 9^7

9 ^ (2-7)

9^ -5

We know that a^ -b = 1/ a^b

1/ 9^5

8 0
3 years ago
Read 2 more answers
Which number is between 3.22 and 3.36? <br> A. 3.2<br> B. 3.93<br> C. 3.37
siniylev [52]

Answer:

a?

Step-by-step explanation:

5 0
4 years ago
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w
pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, the circle is centered at the origin, hence (x_0, y_0) = (0,0).

The circle contains the point (-13,0), hence the radius is found as follows:

x^2 + y^2 = r^2

(-13)^2 + 0^2 = t^2

r^2 = 169

Hence the equation is:

x^2 + y^2 = 169

Then, we test if point (√5, 12) is on the circle:

x^2 + y^2 = 169

(\sqrt{5})^2 + 12^2 = 169

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0
3 years ago
How do you turn 0.23 into a percent
Hitman42 [59]

Answer:

Step-by-step explanation:

you multiply it with 100

0.23 x 100 = 23%

5 0
3 years ago
Read 2 more answers
If f(x) = 3x - 1 and 2f(b) = 28, what is the value of f(2b)?
Vlad1618 [11]
<h3>Answer:  29</h3>

=================================

Work Shown:

Solve the second equation for f(b)

2f(b) = 28

f(b) = 28/2

f(b) = 14

----------

Plug in x = b and solve for b

f(x) = 3x-1

f(b) = 3b-1 ... replace every x with b

14 = 3b-1 ..... plug in f(b) = 14

3b-1 = 14

3b = 14+1

3b = 15

b = 15/3

b = 5

-----------

f(x) = 3x-1

f(2b) = 3(2b)-1 .... replace every x with 2b

f(2b) = 3(2*5)-1 .... plug in b = 5

f(2b) = 3*10-1

f(2b) = 30-1

f(2b) = 29

3 0
3 years ago
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