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Anon25 [30]
3 years ago
10

In the International Grandmaster Championship, a total of 105 games were played where each team played exactly one game with all

the other teams. How many teams were participating in the Championship?
Mathematics
1 answer:
olga2289 [7]3 years ago
3 0

Answer: 15 teams

Step-by-step explanation:

Total number of games played in the tournament = 105

Number of participating teams = p

Each team plays against every other team , then the total number of games played by each team = (p - 1) , since a team can't play itself

To obtain total number of games played =

(Number of teams × number of games played) [p × (p-1)]

However, the teams played against each other only once :

Therefore, total number of games played:

[p × (p-1)] / 2

Since we've been given the total number of games played :

[p × (p-1)] / 2 = 105

p × (p-1) = 105 × 2

p × (p-1) = 210

p^2 - p = 210

p^2 - p - 210 = 0

p^2 - 15p + 14p - 210 = 0

p(p - 15) +14(p-15) = 0

(p - 15) = 0 or (p + 14) = 0

p = 15 or p = - 14

Number of teams can't be negative

Therefore p = 15

Number of teams = 15

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The root found here is 459.

__

<em>Additional comment</em>

In practice, roots are often computed using iterative methods, with some function providing a "starter value" for the iteration. Some iterative methods can nearly double the number of good significant digits in the root at each iteration.

Using this "long division method," each "iteration" adds a single significant digit to the root. Its advantage is that it always works, and is generally suitable for finding roots by hand. Once the number of root digits begins to get large, the "divisor" starts to be unwieldy.

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