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leva [86]
3 years ago
14

there are 1024 players in a tennis tournament in each round half of the players are eliminated which function can be used to fin

d the number of players remaining in the tournament at the end of x rounds
Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer: f(x) = 1,024(0.50)^x

Step-by-step explanation:

Hi, to answer this question we have to apply a decreasing rate formula:

f(x)= P (1 - r) ^x

Where:  

p = original number of players

r = decreasing rate (decimal form, since half of the players are eliminated the percent decrease is 50%)

x = rounds  

f(x) = number of players after x rounds

Replacing with the values given:

f(x) = 1,024(1-50/100)^x

f(x) = 1,024(1-0.5)^x

f(x) = 1,024(0.5)^x

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If the hypotenuse of a right triangle has length 9 feet and one of the other sides has length 2 feet, what is the length of the
alex41 [277]
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Apply Pythagorean theorem

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Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is 9.1\ cm^2

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

A=b^2

where

b is the length side of the square

we have

b=4\ cm

substitute

A=4^2=16\ cm^2

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

A=\pi r^{2}

The diameter of the circle is equal to the length side of the square

so

r=\frac{b}{2}=\frac{4}{2}=2\ cm ---> radius is half the diameter

substitute

A=\pi (2)^{2}

A=4\pi\ cm^2

Therefore, the area of 2 "not-shaded" regions is:

A=(16-4\pi) \ cm^2

and the area of 4 "not-shaded" regions is:

A=2(16-4\pi)=(32-8\pi)\ cm^2

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

so

A=16-(32-8\pi)=(8\pi-16)\ cm^2  

---> exact value

assume

\pi =3.14

substitute

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8 0
4 years ago
The sum of two consecutive odd integers is at most 166. What are the greatest consecutive odd integers?
bagirrra123 [75]
. x + (x + 2)≤166
. 2x+2≤166
. x≤83 - 1
. x≤82
. x=81
. 81+(81+2)=164;  164<166
answer: 81 and 83
4 0
4 years ago
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