There are
ways of drawing a 4-card hand, where

is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are
ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are
ways of picking a card of any given value. We draw 4 cards from the deck, so there are
possible hands in which each card has a different value.
Then there are
total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

24 and 2/5=24+2/5
24=24
0.1=1/10
2/5=x/10
times both sides by 10
20/5=x
4=x
2/5=4/10=0.4
24 and 2/5=24+0.4=24.4
(-1 + 6)^2 <span>+ (4+5)^2 = </span>106
The value of x is 243
(correct me if wrong)
Answer:
8 (7.94)
Step-by-step explanation:
You can think of it as a geometry problem.
What is formed here is a triangle, which sides ate: the line, the line's shadow, and the height from the ground to the kite (here I attach a drawing).
What you need to find is the height. We will call it H.
As the triangle formed is a right one, we can use Pitágoras' theorem. The height H squared plus the squared of the shadow is equal to the squared of the line (the hypotenuse). This is:
H^2 + 9^2 = 12^2
H^2 + 81= 144
H^2 = 63
Applying squared root in both sides
H = √63
H = 7,94
So, the height is approximately 8.