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Murljashka [212]
4 years ago
8

Are 3x and 4(x+1) -x -4 equivalent?

Mathematics
2 answers:
Karo-lina-s [1.5K]4 years ago
6 0

First simplify both sides of the equation:

3x is the most simplified it can be,

4(x+1)-x-4

Use distributive property.......  4(x+1)=4*x+4*1=4x+4  then   4x+4-x-4=3x

so therefore 3x=3x

Answer: YES

Phantasy [73]4 years ago
4 0

Answer: yes both of them are equal


Step-by-step explanation:


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JulsSmile [24]
First you would want to figure out how much tax would be 

127 × 0.08 = 10.16

Then you add the tax to the original price 

10.16 + 127 = 137.16 

And now you have the total cost of the product

137.16
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Which is the best site for online Math and English
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Step-by-step explanation:

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I neeeddddd helppppp it’s urgenttttttt!!!!!!!!
Katyanochek1 [597]

Answer:

x=7

Step-by-step explanation:

The sum of the arc of a circle is 360 degrees

85+5x+5+10x+5+-7+6x+6+17x = 360

Combine like terms

38x+94=360

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38x+94-94 = 360-94

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3 0
3 years ago
Read 2 more answers
Select the correct answer.
maks197457 [2]

Answer:

See Explanation

Step-by-step explanation:

Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.

So, I'll make use of the following expression:

\frac{3n}{n + 3} + \frac{5}{n - 4}

When you follow the steps I'm about to provide, you'll arrive at the right answer

Required

Determine an equivalent expression

\frac{3n}{n + 3} + \frac{5}{n - 4}

Step 1: Take L.C.M of the denominators

LCM = (n+3)(n-4)

Step 2: Evaluate the fractions

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n(n-4)+5(n+3)}{(n+3)(n-4)}

Step 3: Open the brackets at the numerator

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n^2-12n+5n+15}{(n+3)(n-4)}

Step 4: Collect and evaluate like terms

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n^2-7n+15}{(n+3)(n-4)}

<em>Follow the above steps, and you'll be able to solve your question.</em>

6 0
3 years ago
Solve the equation for Imaginary Numbers 1/2(x^2+40)=-12
Nimfa-mama [501]

Answer:

8i and -8i

Step-by-step explanation:

Move everything into the left-hand side to get a quadratic equation:

\frac{1}{2}(x^2+40)=-12\\\frac{1}{2}x^2+20=-12\\\frac{1}{2}x^2+32=0

Solve for x using the quadratic formula:

\frac{1}{2}x^2+32=0\\x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(0)\±\sqrt{0^2-4(\frac{1}{2})32}}{2(\frac{1}{2})}\\x=\±\sqrt{-64}\\x=\±8i

The two imaginary solutions for the equation are 8i and -8i.

3 0
3 years ago
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