The sum of twice a number n and 8 at most 25

Mathematics

1 answer:

mezya [45]3 years ago

6 0

2n + 8 ≤ 25 |subtract 8 from both sides

2n ≤ 17 |divide both sides by 2

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Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached b

Advocard [28]

The question is incomplete.

The complete question is

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached by a real estate agent representing a client who would like to exchange a parcel of land in North Carolina for Kase’s Maryland property. Kase agrees to the exchange.

What is Kase’s realized gain or loss, recognized gain or loss, and basis in the North Carolina property in each of the following alternative scenarios? (Loss amounts should be indicated by a minus sign. Leave no answer blank. Enter zero if applicable.)

a. The transaction qualifies as a like-kind exchange and the fair market value of each property is $907,500.

b. The transaction qualifies as a like-kind exchange and the fair market value of each property is $199,000.

Answer:

A. Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

B. Realised loss ( 199000 - 217000) = 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

Step-by-step explanation:

Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

Here , we find that Kase has realised gain of $ 690,500 but recognised gain of $ 0 . It is so because Kase did not receive any boot and the transaction is a like-kind exchange. Therefore, the adjusted basis in new property = $ 217,000 ( as no gain is recognised ).

Realised loss ( 199000 - 217000 )= 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

7 0

3 years ago

How many of the numbers from 10 through 92 have the sum of their digits equal to a perfect square?

horrorfan [7]

All the numbers in this range can be written as $10d_1+d_0$ with $d_1\in\{1,2,\ldots,9\}$ and $d_2\in\{0,1,\ldots,9\}$ . Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)

so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.

For each number that occupies an entire diagonal in the table, it's easy to see that that number $n$ shows up $n$ times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.

So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.