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4 years ago

Evaluate x + y + z for x = 2, y=-3, z=-4

Mathematics

2 answers:

yKpoI14uk [10]4 years ago

6 0

Answer:

-5 is the answer

Step-by-step explanation:

lorasvet [3.4K]4 years ago

5 0

Answer:

-5

Step-by-step explanation:

You have to plug the numbers for each letter

2 + (-3) + (-4) / 2 - 3 - 4 = -5

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Write the equations of the lines below.

PSYCHO15rus [73]

Answer:

1. y=1x-2

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Step-by-step explanation:

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3 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

The correct option is C.

Step-by-step explanation:

Root Of Complex Numbers

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

4 years ago

9m + 11 - 8m - 6 + 5

RSB [31]

The answer is m+10
I hope that this helps

8 0

3 years ago

Please don't put absurd answers, ty.

dimulka [17.4K]

The answer is decreasing then increasing
Hope this helps!!!!

7 0

3 years ago

Read 2 more answers

432,2=26 275,3=66 342,5=41 123,4=20 then 543,2=?

Readme [11.4K]

Answer:

I think 543,2=24.

hope it helps

5 0

3 years ago

Evaluate x + y + z for x = 2, y=-3, z=-4​

Evaluate x + y + z for x = 2, y=-3, z=-4