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3 years ago

Factor this expression.-12/28b + 15/32

Mathematics

1 answer:

sertanlavr [38]3 years ago

7 0

Answer:

3/4(-4/7b+5/8)

Step-by-step explanation:

3/2(-4/14b+5/16)

3/4(-4/7b+5/8)

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What’s another way to write the equation (40x4)-(32x4)=32

zysi [14]

Answer:

160-128=32

Step-by-step explanation:

distribute what is in the parentheses

7 0

2 years ago

Find the value of y . Please help trying to finish ASAP :)) will give brainliest

slavikrds [6]

Since A (area of circle = C) is given = 148
Where we assume:
Y represents radius of the circle (r)
X represents diameter of the circle (D)
Pi (π) = 3.14
A = 2 * π * y
148 = 2 * 3.14 * y
148 = 6.28 * y
y = 148/6.28
So, y = 23.56

D = 2 * y
D = 2 * 23.56
So, D = 47.12

Assume A is unknown (not given as 148)
A = π * y^2
A = 3.14 * (23.56)^2
A = 3.14 * 47.12
So, A = 147.95 (approx. A = 148)

3 0

3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

Help please! Its late! Xoxo

Mrrafil [7]

Answer:

1)B

Step-by-step explanation:

4 0

3 years ago

Factorise<br><br> x^3 - 2x^2 -x+2

tankabanditka [31]

Answer:

Solution given:

x^3 - 2x^2 -x+2

take common from two each term

x²(x-2)-1(x-2)

take common again and keep left one on other bracket

<u>(x-2)(x²-1) or (x-1)(x+1)(x-2)</u> is a required answer.

note:using formula a²-b²=(a+b)(a-b) for x²-1.

5 0

3 years ago

Read 2 more answers

Factor this expression.-12/28b + 15/32​

Factor this expression.-12/28b + 15/32