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Inessa [10]
3 years ago
7

F

Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

x = 34.8^\circ

Step-by-step explanation:

Given

See attachment for triangle

Required

Find x

To do this, we simply apply sin formula which is:

sin(\theta) = \frac{Opposite}{Hypotenuse}

In this case, it is:

sin(x) = \frac{8}{14}

sin(x) =0.5714

Take arcsin of both sides

x = sin^{-1}(0.5714)

x = 34.84791

x = 34.8^\circ --- approximated

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What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
PLS ANSWER ASAP Find the length of the side labeled x. Round intermediate values to the nearest tenth. Use the rounded values to
irina [24]
The correct answer is c. 16.6


Explain


The triangle left side
Opposite side= hypotheses x sin 0

Plugin

Opposite side = 39 x sin 43

39 x 0.68

26.60


The right side

Opposite side = adjective side x tan0

Opposite side = 26.60 x tan 32

26.60 x 0.62

X= 16.6


Hope this help you :D
6 0
4 years ago
100 POINTS AND BRAINLIEST
zysi [14]

Answer:

8 square units and \frac{40}{3} square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor \frac{1}{3}, then

\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.

2. Triangles ABC and DBE are similar with scale factor \frac{2}{3}, then

\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.

3. Thus, the area of the quadrilateral DFGE is

A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.

and the area of the quadrilateral ADEC is

A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.

4 0
3 years ago
Read 2 more answers
Maria paid $48 for herself and two of her friends to go to a concert. The tickets are all the same price. What equation could be
dimaraw [331]

Answer:

The answer is D. $48 = 3p

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Does 3 tenths equal 4 fifths?
OleMash [197]
No it does not equal 4 fifths
6 0
3 years ago
Read 2 more answers
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