I need to know what the answer to the expression, 1/4(16+4p), is.

Mathematics

2 answers:

NARA [144]4 years ago

8 0

Answer:

5 is the answer

Step-by-step explanation:

Xelga [282]4 years ago

4 0

1/4 (16+4p)

distribute

1/4 * 16 + 1/4 * 4p

4 + p

You might be interested in

A right triangle has a hypotenuse length of 13 units. One leg has a length of 12 units. Which equation can be used to determine

viktelen [127]

a = √(13² - 12²) units

<h3>Further explanation</h3>

<u>Given:</u>

A right triangle has a hypotenuse length of 13 units.
One leg has a length of 12 units

<u>Question:</u>

Which equation can be used to determine the length of the other leg?

<u>The Process:</u>

We will solve a problem regarding right triangles. In the process, there is a relationship between the Pythagorean Theorem with Exponent and Square Root.

Let us find out the equation to determine the length of the other leg. Let the length of the leg as "a".

The Phytagorean Theorem:

$\boxed{ \ (leg)^2 + (leg)^2 = (hypotenuse)^2 \ }$

$\boxed{ \ a^2 + 12^2 = 13^2 \ }$

Subtract by 12² on both sides.

$\boxed{ \ a^2 = 13^2 - 12^2 \ }$

To take the square root on both sides.

So here's the equation that can be used to determine the length of the other leg: $\boxed{\boxed{ \ a = \sqrt{13^2 - 12^2} \ }}$

- - - - - - - - - -

Notes

If we continue working on the above, the results will be as follows:

$\boxed{ \ a = \sqrt{13^2 - 12^2} \ }$

$\boxed{ \ a = \sqrt{169 - 144} \ }$

$\boxed{ \ a = \sqrt{25} \ }$

Hence the length of the other leg equal to a = 5 cm.

Of course, we agree with the use of the right intuition, which is to remember Pythagorean Triples, i.e., $\boxed{ \ 5-12-13 \ }.$ This method is very convenient when working on multiple-choice tests in a limited amount of time.

<h3>Learn more</h3>

What are the lengths of the legs of the triangle? brainly.com/question/13027296
Find out the measures of the two angles in a right triangle brainly.com/question/4302397
A word problem of a quadratic equation brainly.com/question/11805547