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Flauer [41]
3 years ago
15

Allison and Amy Scott work 15 hours per week at separate jobs. Allison assists in a hospital for $5.25 per hour. Amy works in a

restaurant for $3.10 per hour plus tips. Amy averages $38 in tips for the 15 hours. Who earns more each week?​
Mathematics
2 answers:
alexira [117]3 years ago
5 0

Allsion earns $5.25 and hour for 15 hours, so multiply 5.25 * 15 to get her total, which is $78.75.

Amy earns $3.10 an hour for 15 hours so multiply 3.10 * 15 to get her total, which is $46.50 and she gets $38 in tips so add 46.50 + 38 for her grand total of $84.50.

Since Amy earns more each day, she would earn more each week too

lord [1]3 years ago
3 0

Answer:

Amy makes more money

Step-by-step explanation:

Allison:

works 15hr

makes $5.25 per hr

(5.25)15 = 78.75

Allison makes 78.75 per week.

Amy:

works 15hr

makes 3.10 per hour

(3.10)15 = 46.50

plus 38 in tips

46.50 + 38 = 84.50

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a sidewalk is 5ft wide, 6in deep, and 220 ft long. how many cubic yards of concrete are needed to fill it?
tangare [24]

Answer:

1100/54 yds

Step-by-step explanation:

First convert inches and feet to yards

[3 ft = 1 yd, 12in = 1yd]

5ft = 1 2/3 yds

6in = 1/6 yds

220ft = 73 1/3 yds

Now use the volume formula,

b*w*h = A

[1 2/3] * [1/6] * [73 1/3]

= [5/3] * [1/6] * [220/3]

= [5/18] * [220/3]

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3 years ago
Tomas makes balloon sculpture at a circus. In 180 minutes he uses 252 balloons to make balloon sculptures. How many minutes does
Mademuasel [1]

Answer:

0.714 mins

Step-by-step explanation:

by using the rule of three:

180 mins----->252 ballons

x----------------1 ballon=0.714 mins

4 0
3 years ago
Eliminate the parameter and obtain the standard form of the rectangular equation. Ellipse: x = h + a cos(θ), y = k + b sin(θ) Us
gayaneshka [121]

Answer:

a)  (\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1

b)  x=1+5 \,cos(\theta)\,,\,y=4\,sin(\theta)

c)   \frac{(x-1)^2}{25}+ \frac{y^2}{16}=1

Step-by-step explanation:

Start by isolating the trigonometric expression in both equations, ad then use the Pythagorean identity:

cos^2(\theta)+sin^2(\theta)=1

to obtain the standard equation of a conic.

x=h+a\,cos(\theta)\\x-h=a\,cos(\theta)\\cos(\theta)=\frac{x-h}{a}                   y=k+b\,sin(\theta)\\y-k=b\,sin(\theta)\\sin(\theta)=\frac{y-k}{b}

then:

cos^2(\theta)+sin^2(\theta)=1\\(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1

this is the equation of an ellipse centered at (h,k), and with horizontal axis length = 2a , and vertical axis length = 2b.

The parametric equations are those we started with:

x=h+a \,cos(\theta)\,,\,y=k+b\,sin(\theta) but we need to find the appropriate parameters for the requested ellipse, as shown below.

For an ellipse of vertices (-4,0) a,d (6,0) and foci at (-2,0) and (4.0), we are dealing with an ellipse with major horizontal axis on the line y=0, and major diameter length of 10 units, so the parameter a=5. The center of the ellipse is therefore at (1,0).

We recall that the vertices of a translated horizontal ellipse are located at (a+h,k) and (-a+h,k), then k=0 to satisfy the information given (-4,0) & (6,0), and since a=5, we deduce that a+h = 6  and therefore h=1.

To find "b" (the only parameter missing for the standard equation of the conic), we need the information on the foci (-2,0) and (4,0) which must equal (h-c,k) and (h+c,k) with k=0 and h=1 which then gives that c=3

Now using the formula for the parameter "c" of the foci: c=\sqrt{a^2-b^2}

c=\sqrt{a^2-b^2}\\3=\sqrt{5^2-b^2}\\9=25-b^2\\b^2=25-9\\b^2=16\\b=4

Then we can write the equation of this ellipse in standard form as:

(\frac{x-h}{a})^2+ (\frac{y-k}{b})^2=1\\(\frac{x-1}{5})^2+ (\frac{y-0}{4})^2=1\\\\(\frac{x-1}{5})^2+ (\frac{y}{4})^2=1\\\frac{(x-1)^2}{25}+ \frac{y^2}{16}=1

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