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katen-ka-za [31]
3 years ago
5

the points (4, -6) and (9, -6) represent the location of two tons on a coordinate grid. where one unit is equal to one mile. wha

t is the distance, in miles, between the two towns?
Mathematics
2 answers:
Vilka [71]3 years ago
3 0

Answer:5 miles

Step-by-step explanation:

alexdok [17]3 years ago
3 0
The answer to this is 5
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a boy pulls on a 50-kg wagon with a constant force of 400 newtons. what is the wagons acceleration? ​
SVEN [57.7K]

Answer:

8 m/s^2

Step-by-step explanation:

F = ma

400 =  50a

a = 8

7 0
4 years ago
Hi please help me really need it!
adelina 88 [10]

Answer:

C

Step-by-step explanation:

To Solve, just cube the terms on the right side to see if they go back to the number on the left.

The first part is true because multiplying 11 * 11 * 11 = 1331.

The second part is true because multiplying 5 * 5* 5 = 125.

The third part is false because multiplying 8 * 8 * 8 = 512.

The fourth part is true because multiplying 1 * 1* 1 = 1.

8 0
3 years ago
In an election, 471 people voted. Candidate B received 2/3 of the votes. How many votes did Candidate B received?
Lunna [17]

Its 314 because 2/3 times 471

6 0
3 years ago
The area of this square
ANEK [815]

It appears as if 12cm is half the length of the side so we can assume that the total length of one side is 24cm.


The area of a square is given by the equation A=s^{2} where s is the length of the side.  

A=24^{2}

A=576


The area of this square is 576cm2.


Hope this helps!

7 0
3 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
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