BD is the bisector of angle ABC. Find the length of the segment AE.

Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$

Reduce by dividing top and bottom by 2:

$1\frac{1}{15}$

Now for y:

$\frac{3\frac{1}{6}+3\frac{2}{3}}{2}$

Write the mix fractions as improper fractions:

$\frac{\frac{19}{6}+\frac{11}{3}}{2}$

Dividing by 2 is the same as multiplying by 1/2:

$\frac{19}{12}+\frac{11}{6}$

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

$\frac{19}{12}+\frac{22}{12}$

Since the denominators are the same we can write as a single fraction:

$\frac{41}{12}$

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

$3\frac{5}{12}$

So the midpoint is:

$(1\frac{1}{15},3\frac{5}{12})$ .

6 0

2 years ago

Read 2 more answers

PLS HELP ME ASAP FOR 1, 2, 3, and 4 (SHOW WORK!!) + LOTS OF POINTS!!

Lera25 [3.4K]

1/2in = 16 mi
2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator
4×2 = 8 +3 = 11/4
Find common denominator for 1/2 and 11/4 (common D Is 4)
Multiply 1/2 by 2/2
2/4 in = 16 mi divide this by 2
2/4 ×1/2 = 1/4
16 /2 = 8
1/4 = 8
1/4 goes into 11/4 11 times
Multiply 8 times 11
88 miles (D)

End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft
To find scale divide 360 by 6
1in = 60 ft (B)

160 ft wide
(divide 160 by 60 ft ) fraction
160/60 is a fraction now simplify
16/6
Common factors of both numbers is 2
Simplify by 2
8/3
Make into whole number fraction
3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator)
2 2/3 in (B)

120 ft long
80 ft wide

24 in is scale of "long"
Divide 120 by 24
120÷24=5
So 5in in scale equals 1ft in real life
To find width in scale divide 80 by 5
80/5= 16in (A)

If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)

5 0

3 years ago

Does anyone understand how to solve this?

Nataliya [291]

a f(a) is the function f(x) where x is replaced by a.

So we have

(3x^2 + x + 3 - (3a^2 + a + 3)) / ( x - a)

= (3x^2 - 3a^2 + x - a) / (x = a) Answer

b (3(x + h)^2 + x + h + 3 - (3x^2 + x + 3)) / h

= (3x^2 + 6xh + 3h^2 + x + h - 3x^2 - x - 3) ) / h

= (6xh + h + 3 h^2) / h

= 6x + 3h + 1 Answer

6 0

2 years ago

I need help with this question

vladimir1956 [14]

The answer is 2 because it is quadratic equation

7 0

2 years ago

How to inverse this function step by step <br> f(x)=x-3/5

Nitella [24]

f(x)=x3−5

Replace f(x)

with y

.

y=x3−5

Interchange the variables.

x=y3−5

Solve for y

.

Since y

is on the right side of the equation, switch the sides so it is on the left side of the equation.

y3−5=x

Add 5

to both sides of the equation.

y3=5+x

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

y=3√5+x

Solve for y

and replace with f−1(x)

.

Replace the y

with f−1(x)

to show the final answer.

f−1(x)=3√5+x

Set up the composite result function.

f(g(x))

Evaluate f(g(x))

by substituting in the value of g into f

.

(3√5+x)3−5

Simplify each term.

Remove parentheses around 3√5+x

.

f(3√5+x)=3√5+x3−5

Rewrite 3√5+x3

as 5+x

.

f(3√5+x)=5+x−5

Simplify by subtracting numbers.

.

Subtract 5

from 5

.

f(3√5+x)=x+0

Add x

and 0

.

f(3√5+x)=x

Since f(g(x))=x

, f−1(x)=3√5+x is the inverse of f(x)=x3−5

.

f−1(x)=3√5+x

5 0

2 years ago