Which table represents the graph of a logarithmic function with both an x-and y-intercept?

Mathematics

1 answer:

Alex3 years ago

7 0

its the second option on edge

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F(c)= 9/5c+ 32 I just don't understand how to find the inverse of the function

Viefleur [7K]

F = 9/5 C + 32
- 32 -32

subtracting - 32 from both sides

F - 32 = 9/5c
5/9 F -32 = 5/9(9/5)C

Invert 9/5 to 5/9 multiply to both sides

5/9F - 32 = C

The answer is 5/9F-32 = C

5 0

3 years ago

Mmmm! I love apple cider punch this time of year, and so do all my neighbors. My recipe calls for two quarts of apple cyder, thr

pickupchik [31]

Answer:

Step-by-step explanation:

8 0

3 years ago

Please help!!!!!!!!!

Artist 52 [7]

Answer:

1/8 or 0.125

Step-by-step explanation:

hope this helped

6 0

3 years ago

Read 2 more answers

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

Solve. -2 1/4 ÷ (-1 1/2)

Pie

Answer:

=21/22

(Decimal: 0.954545)

hope i helped -lvr

5 0

3 years ago