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= 12 + (- 6)(n - 1 )
This is an arithmetic sequence with n th term
=
+ (n - 1)d
here d = - 6 - 0 = 0 - 6 = 6 - 12 = -6 and = 12, hence
= 12 + (- 6)(n - 1)
use this formula to find the 30 th term
= 12 + (- 6 × 29) = 12 - 174 = - 162
Answer:
(2a, b )
Step-by-step explanation:
Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ (x₁ + x₂ ),
(y₁ + y₂ ) ]
Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus
midpoint = [ (2a + 2a),
(2b + 0 ) ] = (2a, b )