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2 years ago

X^3 = 125 over 27 CAN I PLEASE GET HELP

Mathematics

2 answers:

snow_tiger [21]2 years ago

4 0

It is true that 3×3×3=27 so the cubed root of 27 is 3 how about the cubed root of 125

agasfer [191]2 years ago

3 0

X^3= (125/27)

To find the answer, find the cube root of both sides
x= ∛(125/27)

∛(125/27)= (∛125)/(∛27) = 5/3

Final answer: 5/3

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Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.

Flauer [41]

Answer:

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

Step-by-step explanation:

Given

$\sqrt{128a^{6}b^{13}}$

Required

Solve

$\sqrt{128a^{6}b^{13}}$

The expression can be split to:

$\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}$

So, we have:

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}$

Rewrite as:

$\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

5 0

2 years ago

Which two points satisfy y = -x2 2x 4 and x y = 4?

matrenka [14]

I will assume that the two equations are

1) y = -x^2 +2x + 4 and 2) x +y = 4

subtract 2 from 1 and you get

y -x - y = -x^2 + 2x + 4 - 4

-x = -x^2 +2x

x^2 -x -2x = 0

x^2 - 3x = 0

x(x-3)=0

x=0 and x - 3 =0

x=0 and x = 3

Then y = 4 - x

y = 4 - 0 and y = 4 -3
y = 4 and y =1

Solutions:

Points (0,4) and (3,1)

6 0

3 years ago

Solve. 2x + 3 = 2x - 3

WINSTONCH [101]

Step-by-step explanation:

Respuesta:13

3 0

2 years ago

Read 2 more answers

Korvikt [17]

Answer

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3 0

3 years ago

Given the following information, determine which lines are parallel and what justifies them being parallel.

kow [346]

Answers:

Blank 1 = p and q

Blank 2 = Consecutive interior angles converse

=================================================

Explanation:

There's a lot of visual noise here, meaning there's a lot of lines and angles to potentially distract. I recommend redrawing things but only drawing lines p and q, and the transversal cut line t. Furthermore, I would mark only angle 8 and angle 13. See the diagram below.

The diagram is optional, but hopefully you can see that the angles are same side interior angles, aka consecutive interior angles. That's why we go with the consecutive interior angles converse

If we drop the "converse" portion, then that theorem says parallel lines lead to supplementary consecutive interior angles. The converse just reverses the flow of the logic.

8 0

2 years ago