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2 years ago

Given the graph of the function f(x) below what happens to f(x) when x is a very small positive number?

Mathematics

1 answer:

vladimir2022 [97]2 years ago

4 0

Answer: The correct option is

(B) f(x) is a very large positive number.

Step-by-step explanation: We are given the graph of a function f(x) as shown in the figure.

We are to check what happens to the f(x) when x is a small positive integer.

From the graph, we see that

when x is approaching to 0 from left hand side, then the value of f(x) is approaching to negative infinity.

And,

when x is approaching to 0 from right hand side, then the value of f(x) is approaching to positive infinity.

So, when x is a very smell positive integer, then y is approaching to positive infinity.

That is, the value of f(x) is a very large positive number.

Option (B) is CORRECT.

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A rectangular garden 6 meters wide has a diagonal measuring 10 meters. find the perimeter of the garden.

FromTheMoon [43]

The perimeter would be:
6+6+10+10
12+20
perimeter= 32
HOPE THIS HELPS YOU! ^_^

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2 years ago

1 day 24 hours 60 minutes 60 seconds

torisob [31]

Answer:

86,400

Step-by-step explanation:

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2 years ago

A certain plant runs three shifts per day. Of all the items produced by the plant, 50% of them are produced on the first shift,

Snezhnost [94]

Answer:

0.2941 = 29.41% probability that it was manufactured during the first shift.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: Manufactured during the first shift.

Probability of a defective item:

1% of 50%(first shift)

2% of 30%(second shift)

3% of 20%(third shift).

$P(A) = 0.01*0.5 + 0.02*0.3 + 0.03*0.2 = 0.017$

Probability of a defective item being produced on the first shift:

1% of 50%. So

$P(A \cap B) = 0.01*0.5 = 0.005$

What is the probability that it was manufactured during the first shift?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.005}{0.017} = 0.2941$

0.2941 = 29.41% probability that it was manufactured during the first shift.

6 0

2 years ago

3x+3y=6 and 5x-6y=15

Anna71 [15]

Multiply first equaton by 2 and add to the other equation

6x+6y=12
<u>5x-6y=15 +</u>
11x+0y=27

11x=27
divide both sides by 11
x=27/11

sub back
3x+3y=6
divide both sides by 3
x+y=2
(27/11)+y=2
2 and 5/11+y=2
minus 2 and 5/11 both sides
y=-5/11

x=27/11
y=-5/11
(27/11,-5/11)

7 0

2 years ago

Find the perimeter of the<br> polygon if ZB = ZD.

Butoxors [25]

Answer:

ion

Step-by-step explanation:

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2 years ago