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olchik [2.2K]
3 years ago
9

Find the value of x. Round your answer to the nearest tenth.

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0

Answer:

38

is the correct answer

Masteriza [31]3 years ago
6 0
I believe 38 would be the correct answer
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(12 ÷ 3 + 6) -4 Math help
LekaFEV [45]

Answer:

Well, we have to remember that we must use PEMDAS, or the order of operations, to solve the expression.

<em>Therefore, we must first either divide or multiply anything that is inside of the parentheses. (In this case divide)</em>

12/3=4

(4+6)-4

<em>Now solve what remains in the parentheses.</em>

4+6=10

10-4

<em>Finally, subtract 4 from 10 and get your answer:</em>

6


4 0
3 years ago
Read 2 more answers
72÷x=3.6÷0.015 what is the answer?
lapo4ka [179]

Answer:

The answer you are looking for is x = 3/10

Step-by-step explanation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

72/x = 3.6/0.015 // - 3.6/0.015

72/x-(3.6/0.015) = 0

72/x-240 = 0

72*x^-1 = 240 // : 72

x^-1 = 10/3

-1 < 0

1/(x^1) = 10/3 // * x^1

1 = 10/3*x^1 // : 10/3

3/10 = x^1

x = 3/10

x = 3/10

4 0
3 years ago
Read 2 more answers
I need help please do this for me<br><br> 49 times 3 divided by 7 square it times 1/4 Add 3/4
mylen [45]

Answer:

3/2 or 1.5 or 1 1/2

Step-by-step explanation:

8 0
3 years ago
What is answer for b the variable
borishaifa [10]
Salutations!

-35 = 7b

Isolate the number

-35/7 = b

-5 = b

b is equal to -5

Hope I helped (:

Have a great day!
6 0
3 years ago
Two vertical posts stand side by side. One post is 8 feet tall and the other is 17 feet tall. If a 24 foot wire is stretched bet
lianna [129]

Answer:

The distance between the posts is 3\sqrt{55} feet.

Step-by-step explanation:

In the attached figure, let DB and AC be the posts and let AD be the wire attached to the top of the posts.

BC is the distance between the posts and we need to find BC.

Note that BC = DE

Also, EC = DB = 8m and AE = AC - EC = 17 - 8 = 9 m.

Now, in the right triangle ADE,

AD^{2} =AE^{2} +DE^{2}

24^{2} =9^{2} +DE^{2}

DE^{2} =24^{2} -9^{2}

= (24+9) (24-9)

= 33(15)

= (3 × 11) × (3 × 5)

DE=3\sqrt{55}

Since DE = BC,

BC=3\sqrt{55}

Hence, the distance between the posts is 3\sqrt{55} feet.



7 0
3 years ago
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