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2 years ago

This hard:( i need help :(

Mathematics

1 answer:

olga_2 [115]2 years ago

4 0

Answer:

$33,680 cm^2$

Step-by-step explanation:

The formula needed for this problem is..

$S.A=2(l*w)+2(l*h)+2(w*h)$ .

Given that;

The height of the door= 200cm

The length of the door= 3cm

The width of the door= 80cm

Now, substitute the formula with the information given.

$S.A= 2(3*80)+2(3*200)+2(80*200)$

$S.A= 2(240)+2(600)+2(16000)$

$S.A= 480+1200+32000$

$S.A= 33,680 cm^2$

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17?15

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3 years ago

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Melanie swarm for 142 minutes during her first week of vacation. In her two weeks of vacation she swam for a total of 347 minute

Soloha48 [4]

Answer: Melanie swam 63 minutes more in second week.

Step-by-step explanation:

Given , Time taken by Melanie in first week to swim = 142 minutes

Combined time taken by her in first two weeks in swimming = 347 minutes

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2 years ago

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b.)

Step-by-step explanation:

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2 years ago

Please help! Correct answer only please! I need to finish this assignment by tomorrow.

pentagon [3]

Answer:

0.779

Step-by-step explanation:

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2 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find h'(x)
h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

 h'(x) = 1.44 ------------ > not exist

8 0

2 years ago