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3 years ago

Help!! (is only needed to answer 4 of this questions)(barinly for extra answers)

Mathematics

2 answers:

german3 years ago

4 0

5. 1
6. 8/9
7. 0
8. 1/5
9. 1 1/4
10. 5/6
11. 1/5
12. 1 3/7

if i am correct please give me brainpower because i did a lot :)

Arisa [49]3 years ago

3 0

Step-by-step explanation:

if right then mark me as brainlists

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A 68-year old retiree has a pension savings of $43,000, a 401k of $75,000, and an IRA account of $62,000. Before 2008, he had 2%

Natalija [7]

Answer:

The answer is the IRA

Step-by-step explanation:

If he takes out 2% from each account, the highest penalty will be for the IRA account which is, 6% of 62,000 is $3,720. He will also take 2% of that 62,000 which will be $1,240. The total will be $4,960.

For the 401k account the withdrawal is $1,500 and the penalty is $3,000. That is $460 less than the IRA account.

I hope this answer helps.

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2 years ago

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what is the answer to this question and how??

Lesechka [4]

Answer:

maybe there's a typo, that dot usually represents the multiplication, and I got 5.52

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3 years ago

Looking up, Felipe see two two hot air balloons in the sky shown. He determines that the lower hot air balloon is 515 meters awa

OlgaM077 [116]

Answer:

281.4

Step-by-step

This is the answer

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2 years ago

What is the value of y in the solution to the system of equations? One-thirdx + One-fourthy = 1 2x – 3y = –30 –8 –3 3 8

Neporo4naja [7]

Step-by-step explanation:

1/3x+1/40 =1 2x – 3y = –30 –8 –3 3 8

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3 years ago

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen

sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

$P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444$

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

$P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333$

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172$

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

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