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3 years ago

Write a verbal sentence involving an unknown number and two operations

1 answer:

6 0

Alice has three times more fidget spinners than John. John has 3 fidget spinners. If Alice lost 4 fidget spinners, how many fidget spinners does Alice now have?

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In a box of crayons, 24% of the crayons are blue.There are 48 blue crayons in the box.

-BARSIC- [3]

D. There are 200 crayons in the box. If you just made it 25% of 200 is 50 which is the closest number to answer based on a quick estimation:)

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3 years ago

Where Do Aliens Leave Their Spaceships? **I have the answer key image!!**

nikitadnepr [17]

Write the ictter of the correct answer in the box containing the exercise number. If the answer has a shade in the box

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2 years ago

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.

We will use half life formula.

$A=a\cdot(\frac{1}{2})^{\frac{t}{h}}$ , where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{1}$

$A=1\text{ kg}\cdot\frac{1}{2}$

$A=0.5\text{ kg}$

Therefore, amount of the material left after 10 days would be 0.5 kg.

$A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}$

$A=1\text{ kg}\cdot(\frac{1}{2})^{2}$

$A=1\text{ kg}\cdot\frac{1^2}{2^2}$

$A=1\text{ kg}\cdot\frac{1}{4}$

$A=0.25\text{ kg}$

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0

3 years ago

3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r

vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$ .

Slope-intercept form of equation is given as $y=-2 x-2$ .

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and