Answer:
a) 3.6
b) 1.897
c)0.0273
d) 0.9727
Step-by-step explanation:
Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.
a)
The mean of a Poisson random variable X is μ.
mean=E(X)=μ=3.6.
b)
The standard deviation of a Poisson random variable X is √μ.
standard deviation=S.D(X)=√μ=√3.6=1.897.
c)
The probability for Poisson random variable X can be calculated as
P(X=x)=(e^-μ)(μ^x)/x!
where x=0,1,2,3,...
So,
P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!
P(no case of rabies)=P(X=0)=0.0273.
d)
P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)
P(at least one case of rabies)=1-0.0273=0.9727
Additive inverses combine to get 0. So, k is -1.4. The sum is 0. Hopefully that will help.
Answer:
f^-1(x) = (x -14)/10
Step-by-step explanation:
You can find the inverse function by solving for y:
x = f(y)
Here, that is ...
x = 10y +14 . . . . . use the definition of f(y)
x -14 = 10y . . . . . . subtract 14
(x -14)/10 = y . . . . divide by the coefficient of y
So, your inverse function is ...
f^-1(x) = (x -14)/10
Phillip forgot to put a period between 2 and 50
6785 - 6496 = 289 units
289 x 13p = 3757p
3757p = £37.57
37.57 + 21.45 = £59.02
