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Leni [432]
3 years ago
15

In Exercises 1-3, graph the function. Compare the graph to the graph of

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

  • See the graphs on the document attached.
  • See the explanation on the document attached

Explanation:

I can answer everyone except #6 since the function is garbled.

Take into account this:

  • Vertex general form: y = A(x - h)² + k ⇒ vertex = (h, k)
  • y-intercept ⇒ x = 0
  • x-intercepts ⇒ y = 0
  • Axis of symmetry ⇒ x = h (vertical line that passes through the vertex)
  • A > 0 ⇒ open upward (like an "U" shape)
  • A < 0 ⇒ open downward (like "∩" shape)

See the pdf document attached with every answer because I could not upload the document here.

Download pdf
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The torque required to remove bolts in a steel plate is rated as very high, high, average, and low, and these occur about 30%, 4
Diano4ka-milaya [45]

Answer:

0.004

Step-by-step explanation:

If two events A, B with probabilities P(A), P(B) are independent, then the probability of the two events ocurring at the same time A∩B is P(A)P(B).

In this case we have

P(torque=very high) = 0.3

P(torque=high) = 0.4

P(torque=average) = 0.2

P(torque=low) = 0.01

Using the product rule, we see there are

\frac{25!}{7!8!6!4!}=4.4172*10^{12}

ways of partitioning 25 bolts in groups of 7,8,6 and 4 bolts.

Each one of those partitions has a probability of

(P(torque=very high))^7*(P(torque=high))^8*(P(torque=average))^6*(P(torque=low))^4= (0.3^7)*(0.4^8)*(0.2^6)*(0.1^4)=9.1729*10^{-16}

So, the probability of rating 7 very high, 8 high, 6 average, and 4 low is

4.4172*10^{12}*9.1729*10^{-16}=0.004

5 0
4 years ago
Which of the following equations has both -2 and 2 as possible values of b?
Katena32 [7]

Answer:

C

Step-by-step explanation:

For A it would be 2x2=4 and -2x2 does not equal 4

and dont forget B. is absolut mumbo jumbo

Thus the only sane answer is C.

(:

3 0
3 years ago
I need help on this.
valentina_108 [34]
For 45, 45, 90 angled triangles, the two legs are equal to 'x', and the hypotenuse is equal to \sf x\sqrt{2}. Since we know the length of the hypotenuse, we can set this equal to it:

\sf x\sqrt{2}=8

Divide the square root of 2 to both sides:

\boxed{\sf x\approx 5.657}

So the length of both AC and BC is approximately 5.657.
4 0
4 years ago
Read 2 more answers
Hi please help! Extra points!
xeze [42]

Answer:

The area of the hexagon is approximately 55.43 square feet

Step-by-step explanation:

The given apothem of the hexagon, a = 4 ft.

The area of an hexagon given the apothem, 'a', is found as follows;

The area of an hexagon of side length, s, A = ((3·√3)/2)·s²

s = a·2·tan(180/n)

∴ A = ((3·√3)/2)·(a·2·tan(180/n))²

For an hexagon, n = 6

∴ A = ((3 × √3)/2) × (4 × 2 × tan(180/6))² ≈ 55.43

The area of the hexagon, A ≈ 55.43 ft.²

5 0
3 years ago
In a class of 160 students, 90 are taking math, 78 are taking science, and 62 are taking both math and science. What is the prob
pogonyaev
Add all the numbers together and the difference is the answer which is 44%

7 0
3 years ago
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