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strojnjashka [21]
4 years ago
15

Write an equation for the relationship shown on this graph if the price per ticket is doubled.

Mathematics
1 answer:
Ilya [14]4 years ago
4 0
Easy
so if x is input
y is output
(x,y)
y=2 times x or y=2x

answe ri sy=2x
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What is the measure of the angle in degrees? (Write number in answer only)
masha68 [24]

Answer:

it is 35 degrees

Step-by-step explanation:

I am sure of it

8 0
3 years ago
 If the equation y = 15x + 2 is changed to y = 15x - 4, how will the graph of the line change?
igomit [66]
The y-intercept is changed from 2 to -4.

That means that the point that the graph crosses the y axis has been moved down by 6.

Since the slope of the line has not changed, this just means the graph of the line will be moved down by 6.

Hope this helps!
Your fortune is "When given a difficult choice, trust your gut. If you don't have one, then close your eyes and hope for the best."
6 0
3 years ago
Read 2 more answers
Mario sells electronics at Big Box Electronics Store. He is paid a salary of $250 a week
Usimov [2.4K]

Answer:

Step-by-step explanation:

  1. E = 0.07s + 250
  2. 0.07
  3. Salary per week
  4. What he makes if he doesn't sell anything that week
  5. $4000
6 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
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The mean gpa for 115 residence of the local apartment complex is 1.7.What is the best point estimate for the mean gpa for all re
Anton [14]

Given that the mean GPA for 115 residence of the local apartment complex is:

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