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Inga [223]
3 years ago
13

You have a $20 phone card. Calls made using the card cost $.03 per minute to destinations in the United States and $.06 per minu

te to destinations in Brazil. Write an inequality describing the numbers of minutes you can use for calls to the U.S. and Brazil.
Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:  .03x + .06y ≤ 20

<u>Step-by-step explanation:</u>

Let x represent the number of minutes to the US and

let y represent the number of minutes to Brazil

and make sure their sum is not greater than $20

.03x + .06y ≤ 20

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Answer:

You can go 26 miles

Step-by-step explanation:

15 - 1 = 14

14 ÷ 0.52 = 26.92

4 0
3 years ago
U − -23<br> _______ = -8<br> -9 <br><br> Solve for u<br> Thanks!
Romashka [77]

Answer:

u=95

Step-by-step explanation:

To solve this problem we need to isolate 'u' variable using properties of equation.

Lets multiply by -9 the whole equation

u - -23=-8*9

Remember keys features of algebra:

- * - = +

- * += -

+ * - = -

+ * + =+

So, our equations becomes>

u+23=-72

Lets now subtract 23 to both sides

u-23=-72-23

We have u=95

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3 years ago
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Manny makes dinner using 1 box of pasta and 1 jar of sauce. if pasta is sold in packages of 6 boxes and sauce is sold in package
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The least amount of dinners that Manny can make without any supplies leftover is 3
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3 years ago
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How am i supposed to make a function? Number 15
Greeley [361]

Part A

<h3>Answer: T(n) = 58n+1800</h3>

-------------

Work Shown:

1800 = initial cost or starting cost

58*1 = 58 = cost for one person

58*2 = 116 = cost for two people

58*n = cost for n people

58n+1800 = total cost

58n+1800 = T(n)

T(n) = 58n+1800

======================================

Part B

<h3>Answer: D(T) = 0.85T</h3>

-------------

Work Shown:

T = total bill

15% discount means you still pay 85% of the bill (85%+15% = 100%)

D = discounted cost

D = 85% of T

D = 0.85*T

======================================

Part C

<h3>Answer: D(T(n)) = 49.3n + 1530</h3><h3>See attached image below for the table.</h3>

-------------

Work Shown:

We combine parts A and B.

T(n) = 58n+1800 from part A

D(T) = 0.85*T from part B

D(T(n)) = 0.85*( T(n) )

D(T(n)) = 0.85*( 58n+1800 ) ... plug in T(n) = 58n+1800

D(T(n)) = 0.85*( 58n+1800 )

D(T(n)) = 0.85*(58n)+0.85*(1800) ... distribute

D(T(n)) = 49.3n + 1530

If we plugged in n = 0, then,

D(T(n)) = 49.3n + 1530

D(T(0)) = 49.3*0 + 1530

D(T(0)) = 1530

Or we could plug n = 0 into T(n) to get T(0) = 1800

Then plug T = 1800 into D(T) = 0.85*T to get D(1800) = 1530

Either way you'll get the same answer.

Repeat this (using either method) for n = 50, 100, 150, 200 and you'll get the table of values you see below in the attached image.

======================================

Part D

The D( T(n) ) function allows us to find the discounted cost D for any number n of people that show up.

The input is n, where n is some positive integer less than or equal to 200 (because this is the reception hall's max capacity).

The output is the final discounted cost.

Example: n = 50 is one input which leads to its corresponding output of D( T(n) ) = 3995 as the table shows. So 50 people would have a discounted total cost of $3,995.

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3 years ago
PLEASE HELP ME!! BRAINLIEST AND 60 POINTS
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\boxed{  \tt{its \: a \: straight \: line \: graph}}

3 0
2 years ago
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