Answer:
Solution to determine whether each of these sets is countable or uncountable
Step-by-step explanation:
If A is countable then there exists an injective mapping f : A → Z+ which, for any S ⊆ A gives an injective mapping g : S → Z+ thereby establishing that S is countable. The contrapositive of this is: if a set is not countable then any superset is not countable.
(a) The rational numbers are countable (done in class) and this is a subset of the rational. Hence this set is also countable.
(b) this set is not countable. For contradiction suppose the elements of this set in (0,1) are enumerable. As in the diagonalization argument done in class we construct a number, r, in (0,1) whose decimal representation has as its i th digit (after the decimal) a digit different from the i th digit (after the decimal) of the i th number in the enumeration. Note that r can be constructed so that it does not have a 0 in its representation. Further, by construction r is different from all the other numbers in the enumeration thus yielding a contradiction
Answer:
Right and Isosceles
Step-by-step explanation:
Answer:
v = -0.5
Step-by-step explanation:
v = 2 + (-5 * 1/2)
v = 2 + (-2.5)
v = -0.5
Answer:
The 2 in the hundreths is 10% of the 2 in the tenths
Step-by-step explanation:
We are given the number 15.2201
#The value of 2 in the tenths:
#The value of 2 in the hundredths:
The difference of the 2 in the tenths and in the hundredths is:
Hence, the difference between the 2 in the tenths minus 2 in the hundreths is 0.18, 2 in the hundreths is 10% the 2 in the tenths.
