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3 years ago

Could someone halp meh with dis math plez?

Mathematics

1 answer:

Ne4ueva [31]3 years ago

7 0

I think it's the first question, Jasmine brought some tiles to put around her patio.................... Because if it's looking for area we use the operation multiplication.

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Identify which equations have one solution, infinitely many solutions, or no solution

ipn [44]

Answer:

s+23–s=4.3+s: 1 solution

25+3=2s+-45 : 1 solution

Step-by-step explanation:

4 0

4 years ago

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If 8% tip is given on a dinner bill, and the tip amount was $13.50, how much was the dinner bill after the tip was added?

Nina [5.8K]

Answer: $14.58

Step-by-step explanation: 8% of $13.50 is $1.08 so $1.08 + $13.50 = $14.58

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3 years ago

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A store item is originally priced at $80. The item goes on sale at a 25% discount. Two weeks later that sales price is marked do

DochEvi [55]

25% of 80 is 20 so it is 60. 10% of 60 is 6 so the price is 54.

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3 years ago

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Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$