Question

Trigonometry Trigonometric Functions Given: Sin θ = (5/6), Find: Cot θ

Answer 1

Answer:

cotθ = $\sqrt{11}$ $/ 5$

Step-by-step explanation:

sine = opposite / hypotenuse

cotangent = adjacent / opposite

So first we have to solve for the adjacent side b, using pythagorean theorem

$a^{2} +b^{2} =c^{2}$

$5^{2} +b^{2} =6^{2}$

$25 + b^{2} = 36$

$b^{2} = 11$

$b = \sqrt{11}$

cotangent = adjacent / opposite

cotθ = $\sqrt{11}$ $/ 5$