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3 years ago

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Varia is studying abroad in Europe. She is required pay $3,500 (in US dollars) per year to the university, howere, ahe must pay

in euros. How many euros can Varia expect to pay per month to university? (Round to the nearest whole euro)

1 answer:

kaheart [24]3 years ago

4 0

You would be expected to pay 3,130.00 (3,125.14) Euros.

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After a 40% discount an item costs $360. what is the original cost

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Original Price = Final Price / (100 - Discount)

So...

OP = 360 / 100 - 0.40
OP = 360 / 0.60
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The original price is $600.

To check, do 600 - (600 * 0.40) in a calculator. You get 600 - 240 = 360, the discounted cost.

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3 years ago

Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not

Verizon [17]

Answer: $\left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right$

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

m = $\frac{-3-2}{4-1}$

= $-\frac{5}{3}$

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = $-\frac{5}{3}$ (x - 1)

y - 2 = $-\frac{5}{3}x$ + $\frac{5}{3}$

y = $-\frac{5}{3}x$ + $\frac{11}{3}$

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ $-\frac{5}{3}x$ + $\frac{11}{3}$

8 ___ $-\frac{5}{3}(-2)$ + $\frac{11}{3}$

8 ___ $\frac{1}{3}$

8 > $\frac{1}{3}$

so ≤ makes the statement False

⇒ y ≤ $-\frac{5}{3}x$ + $\frac{11}{3}$

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.

y < 8 or x > -2 are two examples.

---> I just realized that the system can be simpler than what I did above:

$\left \{ {{x>-2} \atop {y < 8}} \right$

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