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MissTica
2 years ago
14

TBH, i am not sure what im doing. Here is a pic of the question.

Mathematics
1 answer:
tatyana61 [14]2 years ago
4 0

Answer:

  7

Step-by-step explanation:

The order of operations tells you to start any evaluation by looking at the innermost set of parentheses first.

Here, that means your first step is to find the value of h(-3). You do that by finding the input (x) value -3 in the table for h(x), and locating the corresponding output, h(x), which is 2.

Now, the problem becomes evaluating g(2).

You do the same thing for that function: locate the input x=2 in the table for g(x) and find the corresponding output: 7.

Now, you know ...

  g(h(-3)) = g(2) = 7

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A theater company charges $3.50 per ticket for people of all age groups. If c represents the total number of children who bought
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The answer is B 3.5(c +a)  because u solving for the total money earned and c is is representing for the company
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3 years ago
Simplify 6/6^1/4 rational exponents
White raven [17]

Answer:

we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

Step-by-step explanation:

Given

The expression is

  • \frac{6}{6^{\frac{1}{4}}}

To determine

Simplify the expression

Simplifying the expression

\frac{6}{6^{\frac{1}{4}}}

Apply the exponent rule:   \frac{x^a}{x^b}=x^{a-b}

\frac{6}{6^{\frac{1}{4}}}=6^{1-\frac{1}{4}}

Subtract the numbers:   1-\frac{1}{4}=\frac{3}{4}

     =6^{\frac{3}{4}}

Therefore, we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

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2 years ago
What is the total weight in ounces of the four heaviest eggs?
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Answer:

6 3/4 ounces

Step-by-step explanation:

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3 years ago
Hayden has $20 to spend at the county fair. Admission to the fair is $5.00 per person, and tickets for food and games are $1.25
Kamila [148]

Answer:

prices of food and games and tickets

6 0
1 year ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B4%7D%20%20-%206%20%7Bx%7D%5E%7B3%7D%20%20%2B%2022%20%7Bx%7D%5E%7B2%7D%20%20-%2
alexira [117]

Answer:

x = 2, 1 + 3i, 1 − 3i

Step-by-step explanation:

Find the Roots (Zeros)

x^4 − 6x^3 + 22x^2 − 48x + 40

Set x^4 − 6x^3 + 22x^2 − 48x + 40 equal to 0. x^4 − 6x^3 + 22x^2 − 48x + 40 = 0

Solve for x.

Factor the left side of the equation.

Factor x^4 − 6x^3 + 22x^2 − 48x + 40 using the rational roots test.

(x − 2) (x^3 − 4x^2 + 14x − 20) = 0

 Factor x^3 − 4x^2 + 14x − 20 using the rational roots test.

(x − 2) (x − 2) (x2 − 2x + 10) = 0

 Combine like factors.

(x − 2)2 (x^2 − 2x + 10) = 0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

(x − 2)^2 = 0

x^2 − 2x + 10 = 0

 Set (x − 2)^2 equal to 0 and solve for x.

Set (x − 2)^2 equal to 0.

 (x − 2)^2 = 0

Solve (x − 2)^2 = 0 for x.

x = 2

 Set x^2 − 2x + 10 equal to 0 and solve for x.

Set x^2 − 2x + 10 equal to 0. x^2 − 2x + 10 = 0

Solve x^2 − 2x + 10 = 0 for x.

Use the quadratic formula to find the solutions.

−b ± (√b^2 − 4 (ac) )/2a

Substitute the values a = 1, b = −2, and c = 10 into the quadratic formula and solve for x.

2 ± (√(−2)^2 − 4 ⋅ (1 ⋅ 10))/2 ⋅ 1

Simplify.

Simplify the numerator.

  x =    2 ± 6i/ 2.1

Multiply 2 by 1

 x =  2 ± 6i/2⋅1

 Simplify

  2 ± 6i/2  

   x = 1 ± 3i

The final answer is the combination of both solutions.

x = 1 + 3i, 1 − 3i

The final solution is all the values that make (x − 2)2 (x2 − 2x + 10) = 0 true.

x = 2, 1 + 3i, 1 − 3i

3 0
3 years ago
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