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Alisiya [41]
3 years ago
6

NEED HELP ASAP PLEASE WITH #2!

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer: The answer is the first bubble

Step-by-step explanation:

1. When you identify the pairs you get: { ( -5,-4), (-1,5), ( -5,3) , (7,8) }

2. When figuring out whether or not it is a function, you have to see if there are any same y values. If there is no y values that are the same, then the relation is a function.

3. This relation is a function.

* Also, if you have a relation that has the two or more of the same x values, the relation is still a function no matter what.

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{(0, 2), (3, 3), (8, 7), (2, 2), (3,9) }
k0ka [10]

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>Here's</em><em> </em><em>your</em><em> </em><em>answer</em><em>:</em>

<h3><em><u>Domain</u></em><em><u>:</u></em><em><u>{</u></em><em><u>(</u></em><em>0</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>8</em><em>)</em><em>}</em></h3><h3><em>Range</em><em>:</em><em>{</em><em>(</em><em>2</em><em>,</em><em>3</em><em>,</em><em>7</em><em>,</em><em>9</em><em>)</em><em>}</em></h3>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>. </em><em> </em><em> </em><em> </em><em> </em>

<h3><em>have</em><em> </em><em>a</em><em> </em><em>great</em><em> </em><em>day</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h3>
5 0
3 years ago
Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0
3 years ago
Find the measures of the angles of a triangle whose angles have a measure of x, 1/2x, and 1/6x. Also, what kind of triangle is i
Alexandra [31]

the sum of the angles in a triangle = 180°, thus

x + \frac{1}{2} x + \frac{1}{6} x = 180

multiply through by 6

6x + 3x + x = 1080

10x = 1080 ( divide both sides by 10 )

x = 108

the angles are 108°, 54° and 18°

Since all the angles are different and the largest is 108°

The triangle is an obtuse scalene triangle


5 0
3 years ago
What is 8 × 1 + 3 × 0.1 + 9 × 0.01 in standard form
emmasim [6.3K]

Answer:

0.216

Step-by-step explanation:

8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216

is this the standard form?

5 0
3 years ago
Hellppppp!!! please??
Wewaii [24]
X1 y4 x 6 and x 6 y 4
5 0
3 years ago
Read 2 more answers
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