At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12
the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12 ⇒⇒⇒⇒ multiplying the equation by 12
∴ 12y = -5x +95
</span>
solution:
You have only two qualitatively different outcomes possible. Count
the number of ways to get each of the two.
There are just two possible outcomes here: the two missing socks
make a pair (the best case) and the two missing stocks do not make a
pair (the worst case). The total number of different outcomes (the ways
to choose the missing socks) is 10 C 2 = 45.
The number of best-case ones is 5; hence its probability is 5 /45 = 1/9
The number of worst-case ones is 45 − 5 = 40; hence its probability is 40/45 = 8/9.
On average, you should expect 4 • 1/ 9 + 3 • 8 /9 = 28/ 9 = 3 1/ 9 matching pairs.
Hi,
The picture you published shows a parabola, if you look at its lowest possible point, that is the vertex, the coordinates are (--2, --8).
Have you understood ?
Green eyes.
Answer:
c the third one with m1 +m3
From the table,
P(selecting a 3) = 0.15
which means that,
P(not a 3) = 1 - P(selecting a 3)
P(not a 3) = 1 - 0.15
P(not a 3) = 0.85
Answer is 0.85
