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Otrada [13]
3 years ago
9

(Adding and Subtracting Polynomials)

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Adding and subtracting big polynomials like these are pretty easy. You just need to combine like terms. For example:

1.)

{5x}^{2}  +  {3x}^{2}  =  {8x}^{2}

2.)

({3x}^{2}  + 5xy) + (7xy + 2) =

{3x}^{2} + 12xy + 2

(The 3x^2 and the 2 stay intact while the 5xy and 7xy combine together)

All you have to do is combine the numbers that have the same powers of x and y with each other. x^2 will combine with x^2 and xy^2 wil combine with xy^2 exc. If there is no other number with the same x and y's, then you just leave it as it is in the answer.

Now with the original question, I see a -9xy^3, and thats gonna combine with the 3xy^3 in the second polynomial and the 2xy^3 in the third one.

- 9x {y}^{3}  + 3x {y}^{3}  + 2x {y}^{3} = \\  - 4x {y}^{3}

So far we have -4xy^3, the next term is going to be a -9x^4y^3, and that's gonna combine with the 3x^4y^3 in the third one.

- 9 {x}^{4} {y}^{3}  + 3 {x}^{4}  {y}^{3}  =  - 6{x}^{4}  {y}^{3}

We now finished adding the like terms that were in the first polynomial, we will move onto the second polynomial. The first term in this one is 3xy^3, in which we already added in the first step. At this point, it doesn't look like there are any other terms that have the same x and y behind them. So we can move on and write the final answer:

- 4x {y}^{3} - 6 {x}^{4} {y}^{3}  + 7 {y}^{4}  \\ - 8 {x}^{4} {y}^{4}

(All on the same line of course)

Also, for your second question, the order does not matter in which you write the terms. I could write the 7y^4 behind the -8x^4y^4 and it would still be the same answer.

If you have any other questions let me know :) while I double check my work.

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Sean's house is currently worth $188,900. According to a realtor, house prices in Sean's neighborhood will increase by 4.8% ever
mrs_skeptik [129]

Answer  

Given

Sean's house is currently worth $188,900.

According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.

To prove

Formula

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Where r is the rate in the decimal form.

As given

Take\ Principle\ = P_{0}

Rate = \frac{4.8}{100}

              = 0.048

Put in the formula

Compound\quaterly\ interest = P_{0}(1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + \frac{0.048}{4})^{4t}

Compound\quaterly\ interest = P_{0} (1 + 0.012)^{4t}       Compound\quaterly\ interest = P_{0} (1.012)^{4t}  

Now also calculated monthly.

Formula

Compound\ monthly = Principle (1 + \frac{r}{12})^{12t}

As given

Take\ Principle\ = P_{0}

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Put in the formula

Compound\ monthly = P_{0} (1 + \frac{0.048}{12})^{12t}

Compound\ monthly = P_{0} (1 + 0.004)^{12t}

Compound\ monthly = P_{0} (1.004)^{12t}

As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .

Thus Option (A) is correct.

i.e

The expression (1.0118)^{4t} reveals the approximate quarterly growth rate of the value of Sean's house.




                                               

                                                       




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