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aivan3 [116]
3 years ago
10

Expand and simplify 9a+3(8-2a).

Mathematics
2 answers:
Zina [86]3 years ago
8 0
9a + 24 - 6a
3a + 24
In bold is your answer
Marianna [84]3 years ago
7 0
3a+24
hope this helps!!!

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Directions: Calculate the area of a circle using 3.14x the radius
Leokris [45]

\qquad\qquad\huge\underline{{\sf Answer}}♨

As we know ~

Area of the circle is :

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 4.4\div 2

\qquad \sf  \dashrightarrow \:r = 2.2 \: mm

Now find the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.2)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {4.84}^{}

\qquad \sf  \dashrightarrow \:area  \approx 15.2 \:  \: mm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 2</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 3.7 \div 2

\qquad \sf  \dashrightarrow \:r = 1.85 \:  \: cm

Bow, calculate the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{}

\qquad \sf  \dashrightarrow \:area  \approx 10.75 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 3 </h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 68.89

\qquad \sf  \dashrightarrow \:area \approx216.31 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 4</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 5.8 \div 2

\qquad \sf  \dashrightarrow \:r = 2.9 \:  \: yd

now, let's calculate area ~

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.9)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  8.41

\qquad \sf  \dashrightarrow \:area  \approx26.41 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 5</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 1 \div 2

\qquad \sf  \dashrightarrow \:r = 0.5 \:  \: yd

Now, let's calculate area ~

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2}

\qquad \sf  \dashrightarrow \:3.14  \times 0.25

\qquad \sf  \dashrightarrow \:area \approx0.785 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 6</h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(8)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 64

\qquad \sf  \dashrightarrow \:area = 200.96 \:  \: yd {}^{2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0
2 years ago
Is the square root of eight a rational or irrational number
shutvik [7]
\bf \sqrt{8}\implies \sqrt{2\cdot 2\cdot 2}\implies \sqrt{2^2\cdot 2}\implies 2\sqrt{2}

it just so happen that √2 is an irrational number, so any product with it as a factor, will yield an irrational number as well.



factoid:   Ancient Greeks were scared of irrational numbers, and they steered clear from √2.
8 0
3 years ago
If abcde is reflected over the x axis and then translated 3 units left, what are the new coordinates C? A. (-2, 2) B (1, 2) C (4
krek1111 [17]

Answer:

A) (-5,-2) B) (-2,-2) C) (1,-2) D) (-7,-2)

Step-by-step explanation:

5 0
3 years ago
Can somebody find the solution to this question
AleksAgata [21]
<h3>Answer: Solution is x = -2</h3>

You have two equations with y1 = f(x) and y2 = g(x).

We're looking for the values of x such that f(x) = g(x). This is the same as trying to solve y1 = y2.

The first row of the table shows y1 and y2 having the same value 5. So we just record the x value that goes with these y values.

5 0
3 years ago
Solve this system of linear equation the x- and y-value with a comma. 18x+13y=60 6x+2y=6
OLEGan [10]

Answer:

18x + 13y = 60

6x + 2y = 6 ---> 6x = -2y +6 ---> 18x = -6y+18

Substitution

(-6y +18)+13y =60

       -18           -18

--------------------------

7y = 42 so y=6

Then, 6x + 2(6) =6, which you will get x = -1

(-1, 6)

8 0
3 years ago
Read 2 more answers
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