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mart [117]
3 years ago
7

Bill is trying to decide what combination of bananas and apples to buy. A banana costs half as much as an apple. If no apples ar

e purchased, he can buy 6 bananas. If no bananas are purchased, he can buy 3 apples. How many apples and bananas will Bill purchase to maximize his total utility?
Business
1 answer:
tia_tia [17]3 years ago
8 0

Answer:

To maximize utility, Bill can will buy one banana and one apple.

Explanation:

Utility maximisation refers to the concept that individuals and firms seek to get the highest satisfaction from their economic decisions.

For example, when deciding how to spend a fixed some, individuals will purchase the combination of goods/services that give the most satisfaction.

The theory of Utility maximization highlights two fators

  • combination of goods
  • Highest satisfaction that is cost effective

if a banana cost half as much as an apple,

Cost of banana = cost of apple/2

cost of apple - cost of banana × 2

Assuming the cost of one banana is $1

The cost of buying 6 bananas = 6×$1 = $6

the same $6 can only buy 3 apples

Therefore the price of apples is $2

If the total amount available = $6,

It can purchase one banana and one apple.

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Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
3 years ago
Micron owns 35% of Martok. Martok pays a total of $47,000 in cash dividends for the period. Micron's entry to record the dividen
creativ13 [48]

Answer:

1. Option (A) is correct.

2. Option (C) is correct.

Explanation:

1. Micron's entry to record the dividend transaction is as follows:

Cash A/c      Dr. $16,450

To Long - Term Investments  $16,450

(In this case, since the holding interest is more than 20%, Equity method is used)

workings:

Dividend = $47,000 × 35%

               = $16,450

2. The entry to record the receipt of dividend would be:

Cash A/c     Dr. $12,000

To Dividend Revenue A/c   $12,000

(To record the receipt of dividend)

Workings:

Dividend = 3,000 shares × $4 per share

               = $12,000

4 0
3 years ago
On December 31 of the current year, the unadjusted trial balance of a company using the percent of receivables method to estimat
Ymorist [56]

Answer: $4,811

Explanation:

Assuming 6% of outstanding accounts receivable at the end of the current year are estimated to be uncollectible that would be,

= 6% * 98,700

= $5,922

The Allowance for Doubtful Accounts acts as a buffer for the business when bad debts are incurred.

Bad debts are taken from the Allowance as the Allowance has already been removed from the Receivables.

In cases where Bad debts exceed the buffer in the Allowance for Doubtful Debt Account we take everything in it and the remaining bad debt amount is debited to Bad Debt expense.

That would be,

= 5,922 - 1,111

= $4,811

$4,811 is the amount that should be debited to Bad Debts Expense.

3 0
4 years ago
Leila has a table in a spreadsheet she wants to format. Which options will allow her to format the table without changing its co
ElenaW [278]

Answer:

All of them, except "Find and replace, Text."

Explanation:

6 0
3 years ago
Which of the following statements is NOT true of a department in the merchandise classification scheme? it is the second level i
Eva8 [605]
The first one is true I think
7 0
3 years ago
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