Define density with a suitable formula

1. ___ Release Of Pressure A. animals that burrow underground

kykrilka [37]

D.3. a.4. sorry this is all i know hope this helps

8 0

3 years ago

A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving

Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle $=29^{\circ}$

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

$y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}$

$y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}$

$y=1.385-0.2368=1.148 m$

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

$h_{max}=\frac{u^2sin^2\theta }{2g}$

$h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}$

$h_{max}=2.02 m$

so deer rises during when it is over fence

8 0

4 years ago

You are riding a skateboard and hit a hole in the street, causing you to fly off the board and crash. Which law represents this

ZanzabumX [31]

Answer:

Newton's first law of motion states that an object at rest will remain at rest and an object in motion will remain in motion unless it is acted on by an unbalanced force. Using unbalanced forces to control the motion of a skateboard demonstrates Newton's first law of motion.

Hope it helps

6 0

3 years ago

Read 2 more answers

There are many well-documented cases of people surviving falls from heights greater than 20.0 m. In one such case, a 55.0 kg wom

bixtya [17]

1a) -192.7g

1b) 0.0126 s

2) 1309 kg m/s

3) $1.04\cdot 10^5 N$

Explanation:

1a)

First of all, we have to find the velocity of the womena just before hitting the ground.

Since the total mechanical energy is conserved during the fall, the initial gravitational potential energy of the woman when she is at the top is entirely converted into kinetic energy.

So we can write:

$mgh=\frac{1}{2}mv^2$

where

m = 55.0 kg is the mass of the woman

$g=9.8 m/s^2$ is the acceleration due to gravity

h = 29.0 m is the initial height of the woman

v is her final speed

Solving for v,

$v=\sqrt{2gh}=\sqrt{2(9.8)(29.0)}=23.8 m/s$

Then, when the woman hits the soil, she is decelerated until a final velocity

$v'=0$

So we can find the deceleration using the suvat equation:

$v'^2-v^2=2as$

where

s = 15.0 cm = 0.15 m is the displacement during the deceleration

Solving for a,

$a=\frac{v'^2-v^2}{2s}=\frac{0-23.8^2}{2(0.15)}=-1888.3 m/s^2$

In terms of g,

$a=\frac{-1888.3}{9.8}=-192.7g$

1b)

Here we want to find the time it takes for the woman to stop.

Since her motion is a uniformly accelerated motion, we can do it by using the following suvat equation:

$v'=v+at$

where here we have:

v' = 0 is the final velocity of the woman

v = 23.8 m/s is her initial velocity before the impact

$a=-1888.3 m/s^2$ is the acceleration of the woman

t is the time of the impact

Solving for t, we find:

$t=\frac{v'-v}{a}=\frac{0-23.8}{-1888.3}=0.0126 s$

So, the woman took 0.0126 s to stop.

2)

The impulse exerted on an object is equal to the change in momentum experienced by the object.

Therefore, it is given by:

$I=\Delta p =m(v'-v)$

where

$\Delta p$ is the change in momentum

m is the mass of the object

v is the initial velocity

v' is the final velocity

Here we have:

m = 55.0 kg is the mass of the woman

v = 23.8 m/s is her initial velocity before the impact

v' = 0 is her final velocity

So, the impulse is:

$I=(55.0)(0-23.8)=-1309 kg m/s$

where the negative sign indicates the direction opposite to the motion; so the magnitude is 1309 kg m/s.

3)

The impulse exerted on an object is related to the force applied on the object by the equation

$I=F\Delta t$

where

I is the impulse

F is the average force on the object

$\Delta t$ is the time of the collision

Here we have:

$I=1309 kg m/s$ is the magnitude of the impulse

$\Delta t = 0.0126 s$ is the duration of the collision

Solving for F, we find the magnitude of the average force:

$F=\frac{I}{\Delta t}=\frac{1309}{0.0126}=1.04\cdot 10^5 N$

7 0

4 years ago

An electron has a mass of 9.1x10-31 kg. What is its momentum if it is travelling at a speed of 3.5x106 m/s?

galben [10]

Answer:

3.19*10^-24

Explanation:

the equation to find momentum is p=mv so you just multiply the mass times velocity

3 0

3 years ago

Define density with a suitable formula​

Define density with a suitable formula