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2 years ago

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Adult men have an average height of 69.0 inches with standard deviation of 2.8 inches fins the night of a man with a z-score of

2.07

1 answer:

ANTONII [103]2 years ago

7 0

What do you mean I’m confused

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A 3 kg model airplane is traveling at a speed of 33 m/s. The operator then increases the speed up to 45 m/s in 2 seconds. How mu

nlexa [21]

Answer:

Force = 18N

Explanation:

Force = [ mass ( final velocity - initial velocity ) ] / time taken

using the formula, here mass is 3 kg, final velocity = 45 m/s , initial velocity = 45 m/s , time taken = 2 seconds

Force = [ 3 ( 45 - 33 ) ] / 2

Force = 18N

8 0

2 years ago

Which of the following are capital cities in the Caribbean? Lima La Habana San Juan San Jos Guinea Ecuatorial

mars1129 [50]

Caribbean:
Habana ... Cuba
San Juan ... Puerto Rico
San Jose ... Costa Rica

Other:
Lima ... capital of Peru in South America
Equatorial Guinea ... country in Africa

5 0

3 years ago

A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad

sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

$\theta = \frac{S}{r}$

where, S = length of the rod

r = radius

Putting the given values into the above formula as follows.

$\theta = \frac{S}{r}$

= $\frac{4}{2}$

= $2 radians (\frac{180^{o}}{\pi})$

= $114.64^{o}$

Now, we will calculate the charge density as follows.

$\lambda = \frac{Q}{L}$

= $\frac{18 \times 10^{-9} C}{4 m}$

= $4.5 \times 10^{-9} C/m$

Now, at the center of arc we will calculate the electric field as follows.

E = $\frac{2k \lambda Sin (\frac{\theta}{2})}{r}$

= $\frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}$

= 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0

3 years ago

Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coef

Alex777 [14]

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

<h3>How to determine the force of friction</h3>

Mass (m) = 81.5 Kg
Coefficient of friction (μ) = 0.7
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
Frictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

<h3>A. How to determine the acceleration</h3>

Mass (m) = 81.5 Kg
Frictional force (F) = 559.09 N
Acceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

<h3>B. How to determine the time </h3>

Initial velocity (u) = 8.23 m/s
Final velocity (v) = 0 m/s
Decceleration (a) = -6.86 m/s²
Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

4 0

2 years ago

A metal disk of radius 6.0 cm is mounted on a frictionless axle. Current can flow through the axle out along the disk, to a slid

Galina-37 [17]

Answer:

0.09 N

Explanation:

We are given that

Radius of disk,r=6 cm= $\frac{6}{100}=0.06 m$

1 m=100 cm

B=1 T

Current,I=3 A

We have to find the frictional force at the rim between the stationary electrical contact and the rotating rim.

$dF=IBdr$

$dF=IBdr$

$\tau=rdF=IBrdr$

$\tau=\int_{0}^{R}IBr dr$

$\tau=IB(\frac{R^2}{2}$

Torque due to friction

$\tau=R\times F$

Where friction force=F

$R\times F=\frac{IBR^2}{2}$

$F=\frac{IBR}{2}$

Substitute the values

$F=\frac{3\times 1\times 0.06}{2}$

$F=0.09 N$

7 0

3 years ago