I believe the correct answer is false. The behaviors that light exhibits are reflection, refraction, diffraction but not polarization, and dispersion. Light<span> behaves as a wave - it undergoes reflection, refraction, and diffraction just like any wave would. Hope this answers the question.</span>
Answer:
The cannon has an initial speed of 13.25 m/s.
Explanation:
The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;
R = u
Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.
R = 26.3 m, H = 19.3 m, g = 9.8 m/
.
So that:
26.3 = u
= 
x 
691.69 = x
= 
= 
= 175.6104
⇒ u = 
= 13.2518
u = 13.25 m/s
The initial speed of the cannon is 13.25 m/s.
A). The sun is highest in London, but will not pass the ship
for another 5 hours.
Since the sun moves from east to west, the ship must be
5 hours west of Greenwich.
Each hour of sun motion is 15° of longitude.
The ship's longitude is (5 x 15°) = 75° West.
The ship may be sailing down Columbia Boulevard
in Maple Shade, New Jersey.
B). The latitude at Buffalo's City Hall is 42.887° North.
Polaris is always within about 2/3 of a degree of that angle
above the northern horizon, when viewed from City Hall.
Choice 2) is the most appropriate.
<u>Answer;</u>
<em>D. The object’s weight changes, but its mass stays the same.</em>
<u>Explanation;</u>
- Mass is the amount of matter in a object, which is measured in kilograms. Mass of an object is measured using a beam balance. It is important to note that the mass of an object or a body remains constant, and does not vary from one place to another. For instance the mass of a person on the moon will be the same as when the person is on the earth surface.
- Weight on the other hand is the measurement of gravitational pull of an object. weight is measured using a spring balance and measured in Newtons. Weight varies from one place to another depending on the gravitational pull of a given surface.
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
