Ask question

Ask question

All categories

2 years ago

13

Adult men have an average height of 69.0 inches with standard deviation of 2.8 inches fins the night of a man with a z-score of

2.07

1 answer:

ANTONII [103]2 years ago

7 0

What do you mean I’m confused

You might be interested in

Describe three clues that tell you that you are o serving a chemical change. Give an Example of each clues you described.

sergiy2304 [10]

1) the object would change color (start to rust or just chnage color)

2) The new substance is ireversable (cant chnage back to original form)

3)theres gas formations (its can change into a gas property)

3 0

3 years ago

Someone help with this table!! 50 points!!!! Please help ASAP!!!!!!

Vesnalui [34]

I have the same thing for homework

8 0

3 years ago

Read 2 more answers

Fill in the blanks. The electrostatic force between two objects is proportional to the ____________________ of the distance ____

Shkiper50 [21]

Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)

F = 900 ÷_________

6 0

3 years ago

Read 2 more answers

What is the relationship of an object's acceleration, its mass and the force applied to it?

Anon25 [30]

Answer:

F = ma

Explanation:

Newtons second law

8 0

3 years ago

The height of a typical playground slide is about 1.8 m and it rises at an angle of 30 ∘ above the horizontal.

Salsk061 [2.6K]

Answer:

$5.94\ \text{m/s}$

$1.7$

$0.577$

Explanation:

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

$\theta$ = Angle of slope = $30^{\circ}$

v = Velocity of child at the bottom of the slide

$\mu_k$ = Coefficient of kinetic friction

$\mu_s$ = Coefficient of static friction

h = Height of slope = 1.8 m

The energy balance of the system is given by

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.8}\\\Rightarrow v=5.94\ \text{m/s}$

The speed of the child at the bottom of the slide is $5.94\ \text{m/s}$

Length of the slide is given by

$l=h\sin\theta\\\Rightarrow l=1.8\sin30^{\circ}\\\Rightarrow l=0.9\ \text{m}$

$v=\dfrac{1}{2}\times5.94\\\Rightarrow v=2.97\ \text{m/s}$

The force energy balance of the system is given by

$mgh=\dfrac{1}{2}mv^2+\mu_kmg\cos\theta l\\\Rightarrow \mu_k=\dfrac{gh-\dfrac{1}{2}v^2}{gl\cos\theta}\\\Rightarrow \mu_k=\dfrac{9.81\times 1.8-\dfrac{1}{2}\times 2.97^2}{9.81\times 0.9\cos30^{\circ}}\\\Rightarrow \mu_k=1.73$

The coefficient of kinetic friction is $1.7$ .

For static friction

$\mu_s\geq\tan30^{\circ}\\\Rightarrow \mu_s\geq0.577$

So, the minimum possible value for the coefficient of static friction is $0.577$ .

8 0

3 years ago