Answer:
$500
Step-by-step explanation:
We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.
<u>Second Discount</u>
20% off means we paid 80%. We know we paid $328 of some price.
I can now cross-multiply by multiplying numerator and denominator from each ratio.
I now solve for y by dividing by 80.
The price after the first discount was $410.
<u>First Discount</u>
We will repeat the steps above with $410. 18% off means we paid 82%.
I can now cross-multiply by multiplying numerator and denominator from each ratio.
I now solve for y by dividing by 82.
The original price was $500.
Factors always multiply each other.
The only option that multiplies something is (y^3 + 3)
So the answer is B.
Answer:
Option (1)
Step-by-step explanation:
System of equations can be written as,
Therefore, system of equations given in Option (1) is the correct option.
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588