1572/6 = 262 which is an integer so x could be 2
X could also be 8 because 1578/6 is 263
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
The longest two sides will be 4 each and the shortest two sides will be 2 each
