Cos9xcos4x help me please

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be

babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0

3 years ago

A recipe calls for cup of broth. The largest volume-measuring tool that Tabitha has is a teaspoon. She knows that there are 16 t

Artist 52 [7]

1c = 16t = x( $\frac{1}{3}$ )
1c = 16t = 16 X 3
1c = 16t = 48

She should use 48 teaspoons of broth.

5 0

3 years ago

Read 2 more answers

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

Jane needs to pay $36 for 2 basketballs, how much she needs to pay 3 basketballs?

OLga [1]

36 divided by 2 is 18

That mean each basketball is $18

18 dollars multiplied by 3 basketballs is 54

Three basket balls cost $54

5 0

3 years ago

Read 2 more answers

Professor Turner wrote the expression below on the chalkboard for his team at the Research Center. He asked the scientists there

Lynna [10]

Answer:

12x + 18y + 6z + 4x - 4z

Step-by-step explanation:

Given the expression : 3(4x + 6y + 2z) + 4(x – z)

To eliminate the parenthesis ; we use the distributive property :

3(4x + 6y + 2z) + 4(x – z) becomes ;

3*4x + 3*6y + 3*2z + 4*x + 4*-z

12x + 18y + 6z + 4x - 4z

Hence,

12x + 4x + 18y + 6z - 4z

16x + 18y + 2z

6 0

2 years ago